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Alexeev081 [22]
3 years ago
11

Point r divides ef¯¯¯¯¯ in the ratio 1 : 5. if the coordinates of e and f are (4, 8) and (11, 4), respectively, what are the coo

rdinates of r to two decimal places?

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
5 0
See the attachment for detailed answer
<span>So then R is 1/6 of the way from E to F.
The x distance from E to F is 11- 4=7.
So then the x distance from E is,
Similarly for y,

R:(31/6,22/3)</span>

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Setler [38]
10x+25 (expressions don't have equal signs)
4 0
3 years ago
Read 2 more answers
Determine the number of real solutions for each of the given equations. Equation Number of Solutions y = -3x2 + x + 12 y = 2x2 -
rosijanka [135]

Answer:

Step-by-step explanation:

Our equations are

y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by  D and its formula is

D=b^2-4ac\\

Where

a= the coefficient of the x^{2}

b= the coefficient of x

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant  and evaluate our answer accordingly .

Let us start with

y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\

Hence we have two real roots for this equation.

y = 2x^2 - 6x + 5\\

y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D

Hence we do not have any real root for this quadratic

y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\

Hence D>0 and thus we have two real roots for this equation.

y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\

Hence we have one real root to this quadratic equation.

7 0
3 years ago
Please help ASAP!!<br><br><br> Will Mark Brainiest
mr Goodwill [35]
I am pretty sure its JT
7 0
3 years ago
Someone please help me
Inessa05 [86]

9514 1404 393

Answer:

  A.  16°

Step-by-step explanation:

Angle E corresponds to angle N, the third angle in ∆MNO. Its measure is ...

  ∠N = 180° -∠M -∠O

  ∠N = 180° -99° -65°

  ∠N = ∠E = 16°

6 0
2 years ago
What are the circumference and area of a circle with radius 7in. Round to the nearest tenth.
Natalka [10]

Circumference is 40 in and area is 150 in²

Step-by-step explanation:

  • Step 1: Find the circumference of the circle when radius = 7 in

Circumference = 2πr = 2 × 22/7 × 7 = 44 in ≈ 40 in

  • Step 2: Find the area of the circle.

Area = πr² = 22/7 × 7² = 154 in² ≈ 150 in²

4 0
3 years ago
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