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skelet666 [1.2K]
3 years ago
14

Write 4x5 3/8 as a mixed number

Mathematics
1 answer:
Sholpan [36]3 years ago
4 0
4 * 5? than it is 20

3/8 would be 0.375
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Find two solutions of y=2x-3<br> Point 1: (x,y) ---&gt;<br> Point 2: (x,y) ---&gt;
Ksenya-84 [330]

The slope of the line is 2/1 and the y-intercept is (0,-3). Using that information, we can figure out two points on the line.

Point 1: (0,-3)

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What is the equation of the line that passes through the points (−2,4) and (0,3)?
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3 years ago
Select all the statements that are true
masya89 [10]

Answer:

Options 2, 4 and 6 are True.

Step-by-step explanation:

Triangle MNO is dilated by a scale factor of \frac{3}{2} centered at M(0, 6).

Rule to be followed to dilate the vertices of the given triangle,

(x, y) → (kx, ky)

Here, k = scale factor

By this rule vertices of the new triangle M'N'O' will be,

M(0, 6) → M'(0, 6) [Coordinates of M' will remain same as M because center of dilation is point M]

N(-4, -4) → N'(-6, -6)

O(6, -2) → O'(9, -3)

Option 1

M'N' is shorter than MN

Distance between M and N = \sqrt{(0+4)^2+(6+4)^2}

                                              = 10.77

Distance between M' and N' = \sqrt{(0+6)^2+(6+6)^2}

                                                = 13.42

Therefore M'N' > MN

Therefore, Option A is False.

Option 2

ON is shorter than O'N'

True.

Option 3

OM is longer than O'M'

False

Option 4

ON is parallel to O'N'

Since OM and MN are dilated with the same scale factor, O'N' will be parallel to ON.

True.

Option 5

OM is parallel than O'M'

Since, O'M' is the dilated form of OM,

Therefore, all the points (O, M and M') will be in a straight line.

False

Option 6

M'N' coincide with MN

True.

Therefore, Options 2, 4 and 6 are True.

3 0
3 years ago
A backyard pool has a concrete walkway around it that is 5 feet wide on all sides. The total are of the pool and the walkway is
mrs_skeptik [129]

Answer:

Step-by-step explanation:

<u>Pool:</u>

Width = x ft

Length = (x+6) ft

<u>Pool along with walkway:</u>

Width = x + 5 + 5 = (x + 10) ft

Length = x + 6 + 5 + 5 = (x + 16) ft

Total area of the pool with walkway = 950 sq.ft

length * width = 950

(x+16) * (x + 10) = 950

Use FOIL method,

x*x + x *10 + 16*x + 16 *10 = 950

x² + 10x + 16x + 160 -950 = 0   {Add like terms}

x² + 26x - 790 = 0

6 0
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