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Sunny_sXe [5.5K]
2 years ago
14

Can u plz help me i have 2 more to day after this one

Mathematics
2 answers:
gavmur [86]2 years ago
7 0

\frac{5 {}^{2}  \times  {5}^{6} }{5 {}^{4} }  \\  { \frac{5}{5 {}^{4} } }^{2 + 6}  \\   \frac{ {5}^{8} }{5 {}^{4} }  \\ 5 {}^{8 - 4}  \\ 5 {}^{4}

so 5⁴ is the answer

Shalnov [3]2 years ago
6 0

Answer:

?=4

Step-by-step explanation:

\frac{5^2*5^6}{5^4}=5^?\\ \\\frac{5^{2+6}}{5^4}=5^?\\ \\\frac{5^8}{5^4}=5^?\\\\5^{8-4}=5^?\\\\5^4=5^?\\\\?=4

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 the number of Significant Figures in 13410000 *​
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Answer:

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Step-by-step explanation:

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2 years ago
Read 2 more answers
Instructions:select all the correct locations on the tables. andrew wants to purchase a new television with a screen length that
DaniilM [7]

The <em>correct answers</em> are:


5x²+70x+245 ≥ 1050; and

Yes.


Explanation:


Let x be the width of the tablet. Since the width of the TV is 7 inches more than the tablet, the width of the TV would be x+7.


The length of the TV is 5 times the width; this makes the length 5(x+7) = 5x+35.


The area of the TV would be given by

(x+7)(5x+35).


Since Andrew wants the area to be at least 1050, we set the expression greater than or equal to 1050:

(x+7)(5x+35) ≥ 1050


Multiplying this, we have:

x*5x+x*35+7*5x+7*35 ≥ 1050

5x²+35x+35x+245 ≥ 1050


Combining like terms,

5x²+70x+245 ≥ 1050


To see if 8 is a reasonable width for the tablet, we substitute 8 for x:

5(8²)+70(8)+245 ≥ 1050

5(64)+560+245 ≥ 1050

320+560+245 ≥ 1050

1125 ≥ 1050


Since this inequality is true, 8 is a reasonable width.

5 0
3 years ago
X^2 + 5x = quadratic equation <br>=​
timama [110]

Hi there!

The question gives us the quadratic equation , and it tells us to solve it using the quadratic formula, which goes as . However, we must first find the values of a, b, and c. The official quadratic equation goes as , which matches the format of the given quadratic equation. Hence, the value of a would be 1, the value of b would be 5, and the value of c would be 3. Now, just plug it back into the quadratic equation and simplify to get the zeros of the equation. 

x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}  

x = \frac{-(5) \pm \sqrt{(5)^2 - 4(1)(3)} }{2(1)}  

x = \frac{-5 \pm \sqrt{25 - 12} }{2}  

x = \frac{-5 \pm \sqrt{13} }{2}  

x = \frac{-5 \pm 3.61 }{2}  

x = \frac{-5 + 3.61 }{2}, x = \frac{-5 - 3.61 }{2}

x=-0.695 \ \textgreater \ \ \textgreater \  -0.7, x= -4.305 \ \textgreater \ \ \textgreater \ x=-4.31

Therefore, the solutions to the quadratic equation  are x = -0.7 and x = -4.31. Hope this helped and have a phenomenal day!

Your answer is 4.31

4 0
3 years ago
The authors of a paper presented detailed case studies to medical students and to faculty at medical schools. each participant w
salantis [7]

Answer:

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3 years ago
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