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julsineya [31]
3 years ago
7

PLEASE HELP! I WILL MARK THE BRAINLIEST!

Mathematics
1 answer:
Anarel [89]3 years ago
7 0

Answer:

2x+3y=-6

Step-by-step explanation:

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The youth group is going on a trip to the state fair. The trip costs $63. Included in that price is $13 for a concert ticket and
Pepsi [2]
Hey there!

63 =  13 + 2P  subtract 13 from both sides

50 = 2P          divide both sides by 2

25 = P 

So the cost of one pass = $25


Hope this helps!

7 0
3 years ago
9&gt;d, if d=3 <br> True or false
Strike441 [17]

Answer:

This is true. 9 is greater than 3.

4 0
3 years ago
Read 2 more answers
Find -3a2 - b3 + 3c2 - 2b3 if a = 2, b = -1, and c = 3
Studentka2010 [4]
If you would like to solve - 3 * a^2 - b^3 + 3 * c^2 - 2 * b^3, if a = 2, b = -1, c = 3, you can calculate this using the following steps:

a = 2, b = -1, c = 3
- 3 * a^2 - b^3 + 3 * c^2 - 2 * b^3 = - 3 * 2^2 - (-1)^3 + 3 * 3^2 - 2 * (-1)^3 = - 3 * 4 - (-1) + 3 * 9 - 2 * (-1) = - 12 + 1 + 27 + 2 = 18

The correct result would be 18.

6 0
3 years ago
Read 2 more answers
What whole number dimensions would allow the students to maximize the volume while keeping the surface area at most 160 square f
ycow [4]

Answer:

The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft

Step-by-step explanation:

Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²

For maximum volume, the side length, s of the cube must all be equal ;

Therefore area of one side = s²

Number of sides in a cube with top open = 5 sides

Area of surface = 5 × s² = 180

Therefore s² = 180/5 = 36

s² = 36

s = √36 = 6 ft

Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.

6 0
3 years ago
15 POINTSSS<br> Need Anwsered Asap!
german
The equation we will use here is A^2+B^2=C^2, which is also know as the Pythagorean Theorem.
The given values are 6 and 9, where they can represent any value, there true values in the equation would be 36(6), and 81(9), so you must select a value that makes the equation true, given the constraints.

with that being said 3, doesnt work because
·36(6)+9(3)≠81(9)
·9(3)+81(9)≠36(6)
·36(6)+81(9)≠9(3)

10 doesnt work either because
·36(6)+81(9)≠100(10)
·81(9)+100(10)≠36(6)
·100(10)+36(6)≠81(9)

12 doesnt work either because 
·144(12)+36(6)≠81(9)
·36(6)+81(6)≠144(12)
·81(9)+144(12)≠36(6)

If you see where this is going you would know that there is no valid solution here, however rounding is always a possibility, when you actually do the math 81(9)+36(6)=117, and when squared you get your answer of 10.8, and the closest answer is 10, there fore your answer would be 10

-I hope this is the answer you are looking for, feel free to post your questions on brainly at any time.



5 0
3 years ago
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