The sides of the triangle are given as 1, x, and x².
The principle of triangle inequality requires that the sum of the lengths of any two sides should be equal to, or greater than the third side.
Consider 3 cases
Case (a): x < 1,
Then in decreasing size, the lengths are 1, x, and x².
We require that x² + x ≥ 1
Solve x² + x - 1 =
x = 0.5[-1 +/- √(1+4)] = 0.618 or -1.618.
Reject the negative length.
Therefore, the lengths are 0.382, 0.618 and 1.
Case (b): x = 1
This creates an equilateral triangle with equal sides
The sides are 1, 1 and 1.
Case (c): x>1
In increasing order, the lengths are 1, x, and x².
We require that x + 1 ≥ x²
Solve x² - x - 1 = 0
x = 0.5[1 +/- √(1+4)] = 1.6118 or -0.618
Reject the negative answr.
The lengths are 1, 1.618 and 2.618.
Answer:
The possible lengths of the sides are
(a) 0.382, 0.618 and 1
(b) 1, 1 and 1.
(c) 2.618, 1.618 and 1.
Answer:
The new amount is 8.
Step-by-step explanation:
80% of 40 is 32, so subtract 32 from 40 to get 8.
93 x 2 = 186
x = 186 - 112
x = 74
y = 2(80) - 74
y = 160 -74
y = 86
360 - 112 - 74 - 86 = 88
z = (88+86)/2
z = 87
Divisibility by 2 would be the correct answer. Two is an even number, and the only listed at that. Odd numbers are only divisible by another odd number. Hope I helped you !
Answer:
3√3
Step-by-step explanation:
If sinx = 4/8, find Cos (6x)
we need to first find cos
but applying trigonometry rule
sin²x+cos²x = 1
sinx = 4/8
sin²x = (4/8)² = 4²/8² = 16/64
from the rule
cos²x= 1 -sin²x = 1-16/64 = 64-16/64 = 48/64 = 3/4
cos²x = 3/4
cos x = √3/4 = √3/2
cos 6x = 6 x √3/2 = 3√3
