Options:
A) Cells require much less P to grow than N, so extra P will be used for ATP synthesis and result in a faster growth rate.
B) Cells will never consume all of the phosphate, because N is needed in higher quantities than P.
C) The final biomass of cells will be no different than if only 50% of the phosphate was provided.
D) The bacteria will import all of the ammonia to use for biosynthetic pathways.
Answer:A) Cells require much less P to grow than N, so extra P will be used for ATP synthesis and result in a faster growth rate.
Explanation: Chemoorganoheterophic Bacteria are bacteria which requires the supply of organic nutrients of Carbon and metabolic energy. If Ammonia and potassium are provided at equal amount or concentration, the least likely occurrence will be that
Cells require much less P(potassium) to grow than N(Nitrogen), so extra P(potassium) will be used for ATP synthesis and result in a faster growth rate. This is so because Chemoorganoheterophic Bacteria requires organic supply of nutrients in the form of Carbon and metabolic energy.
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Gram-positive and Gram-negative are different in their resistance to antibiotics. It is because of their different structure of cell wall. Gram-positive bacteria have a thick peptidoglycan cell wall and dyes purple in the Gram test (for categorization of bacteria). Gram-negative bacteria have thin peptidoglycan layer and do not turn purple. Gram-positive bacteria are easier to kill because their thick peptidoglycan layer absorbs antibiotics.
The correct answer is letter A. The DNA in mitochondria is passes from mother to child in the nucleus of a cell. The s<span>tatement that accurately describes how identification of individuals through the use of genetic engineering is possible is that t</span>he DNA in mitochondria is passed from mother to child in the nucleus.
