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3 years ago

I NEED HELP QUICK ASAP!

Mathematics

2 answers:

kramer3 years ago

8 0

Triangle 1 area : 6×4 /2 -> 24/2 -> 12
triangle 2 area : 9×8 /2 -> 72/2 -> 36
rectangle 1 area : 6×4 -> 24
rectangle 2 area : 15×4 -> 60
12+36+24+60
48+24+60
72+60
132

mel-nik [20]3 years ago

6 0

Area of the large rectangle : 4x15 = 60

Area of the small rectangle : 4x6 = 24

Area of the small right triangle : (4x6)/2 = 12

Area of the large right triangle : High = 8 & side =15-6=9
So its area is( 8x9)/2 =36

Total area =60+24+12+36 = 132 units²

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Solve -vp+40<95 for v

Leya [2.2K]

-vp+40<95

subtract 40 from each side

-vp < 55

divide by -p (which flips the inequality) assuming p>0

v > -55/p

5 0

3 years ago

Use the discriminant to predict the nature of the solutions to the equation 4x-3x²=10. Then, solve the equation.

AleksandrR [38]

Answer:

Two imaginary solutions:

x₁= $\frac{2}{3} -\frac{1}{3} i\sqrt{26}$

x₂ = $\frac{2}{3} +\frac{1}{3} i\sqrt{26}$

Step-by-step explanation:

When we are given a quadratic equation of the form ax² +bx + c = 0, the discriminant is given by the formula b² - 4ac.

The discriminant gives us information on how the solutions of the equations will be.

If the discriminant is zero, the equation will have only one solution and it will be real
If the discriminant is greater than zero, then the equation will have two solutions and they both will be real.
If the discriminant is less than zero, then the equation will have two imaginary solutions (in the complex numbers)

So now we will work with the equation given: 4x - 3x² = 10

First we will order the terms to make it look like a quadratic equation ax²+bx + c = 0

So:

4x - 3x² = 10

-3x² + 4x - 10 = 0 will be our equation

with this information we have that a = -3 b = 4 c = -10

And we will find the discriminant: $b^{2} -4ac = 4^{2} -4(-3)(-10) = 16-120=-104$

Therefore our discriminant is less than zero and we know that our equation will have two solutions in the complex numbers.

To proceed to solve the equation we will use the general formula

x₁= (-b+√b²-4ac)/2a

so x₁ = $\frac{-4+\sqrt{-104} }{2(-3)} \\\frac{-4+\sqrt{-104} }{-6}\\\frac{-4+2\sqrt{-26} }{-6} \\\frac{-4+2i\sqrt{26} }{-6} \\\frac{2}{3} -\frac{1}{3} i\sqrt{26}$

The second solution x₂ = (-b-√b²-4ac)/2a

so x₂= $\frac{-4-\sqrt{-104} }{2(-3)} \\\frac{-4-\sqrt{-104} }{-6}\\\frac{-4-2\sqrt{-26} }{-6} \\\frac{-4-2i\sqrt{26} }{-6} \\\frac{2}{3} +\frac{1}{3} i\sqrt{26}$

These are our two solutions in the imaginary numbers.

7 0

3 years ago

What are the holes, VA, domain, HA, and Range of n+8/6n? Please help!!

-BARSIC- [3]

Answer:

We show that f(x) n+8/6n = 6 x n = 0

which flips the n+8/1 = 0+8/0-6= x = 3 this is the range.

For the HA we would work left to right.

x goes to positive or negative infinity and is determined by the highest degree terms of the polynomials in the numerator and the denominator. This particular function has polynomials of degree 0 in both the numerator and the denominator

If say n+8 was n+2 then we would use the 2/-2+3 and get 1 and show the hole as the source;

hole : -2+1 as non equal sign. but not in the case of n+8/6n

-2+1 represents 1/3 symmetry.

We see for n+8/6n with interpreted back into the zero format minus

-0+8/-0-6 we see there is symmetry and can work on the left side of graph and flip over. Where 0 = n+8 and 1=nx6

Step-by-step explanation:

There would be no way of doing the others unless the exponents had been squared ^2

If they were squared then the domain will be (-infinity -3) parenthesis

union of( -3 -2) union of +2 to negative infinity.

There is not a vertical asymptote as the numerator divides into dominator at point 8 as a decimal.

The holes are then closed.

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3 years ago

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Bezzdna [24]

Answer:

9x/-1 is the correct answer

Step-by-step explanation:

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3 years ago

Solve the following equation x + 8=6

emmainna [20.7K]

Answer:

x = 14

Step-by-step explanation:

1 Add 8 to both sides.

x=6+8

2 Simplify 6+8 to 14.

x=14

3 0

4 years ago

Read 2 more answers