Answer:
It is observed that when a compass is brought near a current carrying conductor the needle of compass gets deflected because of flow of electricity. This shows that electric current produces a magnetic effect.
Answer:
Explanation:
Radius = 9.5 x 10⁻² m
area of circle = 3.14 x (9.5 x 10⁻² )²
A = 283.38 x 10⁻⁴ m²
magnetic moment = area x current
M = 283.38 x 10⁻⁴ x 5
= 1416.9 x 10⁻⁴ Am²
Torque = MBsinθ
M is magnetic moment , B is magnetic field .
Max torque = 1416.9 x 10⁻⁴ x 3.4 x 10⁻³ , for θ = 90
= 4817.46 x 10⁻⁷
= 481.7 x 10⁻⁶
= 481.7 μ J
Energy = - MBcosθ
Max energy when θ = 180
MB = 4817.46 x 10⁻⁷ J
Min energy = - 4817.46 x 10⁻⁷ for θ = 0
<u><em>How Does Matter And Energetic Interact To Produce Weather Patterns?</em></u>
<h3>Weather is caused by different levels of humidity and the difference in the temperature of air which causes wind patterns. Energy from the sun evaporates the water on land. Air also heats up which brings up the water vapor to the atmosphere. This increases the humidity and the chance of rain. When hot is found near the land, this will create a high pressure which will prevent the formation of clouds and produce a fair weather.</h3>
Answer:
a) 
b) 
c) 
d) No,
No.
Explanation:
Given:
length of rope, 
weight of the rope, 
mass suspended at the lower end of the rope, 
<u>Now the mass of the rope:</u>
<u>So the linear mass density of rope:</u>
We know that the speed of wave in a tensed rope is given as:
where:
tension force in the rope
a)
At the bottom of the hanging rope we have an extra mass suspended. So the tension at the bottom of the rope:
Therefore the speed of the wave at the bottom point of the rope:
b)
Tension at a point in the middle of the rope:
Now wave speed at this point:
c)
Tension at a point in the top of the rope:
Now wave speed at this point:
d)
Tension at the middle of the rope is not the average tension of tension at the top and bottom of the rope because we have an extra mass attached at the bottom end of the rope.
Also the wave speed at the mid of the rope is not the average f the speeds at the top and the bottom of the ropes because it depends upon the tension of the rope at the concerned points.
Answer:
l3/l = 2
Explanation:
Suppose B1 is the magnetic field due to cable 1 and B2 is the field due to cable 2. Therefore, the magnitude of the field at a distance from the cable is equal to:
B = (uo*I)/(2*pi*r)
B1-2 = (B1^2 + B2^2)^1/2 = ((((uo*I)/(2*pi*r)^2 + (uo*I)/(2*pi*r)^2))))))^1/2 = (2^1/2)*(uo*l)/(2*pi*r)
From this equation we can say that the direction of the field will be from the corner that is empty and cable 3:
B3 = B1-2
(uo*l3)/(2*pi*(2^1/2)*r = (2^1/2)*(uo*l)/(2*pi*r)
From here we have that the relationship between both currents will be equal to:
l3/l = 2
