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const2013 [10]
3 years ago
15

A wire is formed into a circle having a diameter of 19.0 cm and placed in a uniform magnetic field of 3.40 mT. The wire carries

a current of 5.00 A. (a) Find the maximum torque on the wire. µN · m (b) Find the range of potential energies of the wire–field system for different orientations of the circle. minimum µJ maximum µJ
Physics
1 answer:
nikklg [1K]3 years ago
7 0

Answer:

Explanation:

Radius = 9.5 x 10⁻² m

area of circle = 3.14 x (9.5 x 10⁻² )²

A = 283.38 x 10⁻⁴ m²

magnetic moment = area x current

M = 283.38 x 10⁻⁴ x 5

= 1416.9 x 10⁻⁴  Am²

Torque = MBsinθ

M is magnetic moment , B is magnetic field .

Max torque = 1416.9 x 10⁻⁴  x 3.4 x 10⁻³ , for θ = 90

= 4817.46 x 10⁻⁷

= 481.7 x 10⁻⁶

= 481.7 μ J

Energy = - MBcosθ

Max  energy  when θ = 180

MB = 4817.46 x 10⁻⁷ J

Min energy = - 4817.46 x 10⁻⁷  for θ = 0

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Answer:

12.5J

Explanation:

Given parameters:

Mass of bucket  = 1.7kg

Height  = 75cm  = 0.75m

Unknown;

Work done on the bucket by the person  = ?

Solution:

To solve this problem, we use the work done equation;

  Work done  = force x distance  = mgh

 m is the mass  

  g is the acceleration due to gravity

  h is the height

Now, insert parameters and solve ;

     Work done  = 1.7 x 9.8 x 0.75  = 12.5J

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3 years ago
A student walks 50 meters east, 40 meters north, 35 meters east, and then 20 m south. What is the magnitude and direction of the
Nuetrik [128]

Answer: A student walks 50 meters east, 40 meters north, 35 meters east, and then 20 m south. Then the magnitude and direction of the student's total displacement will be 87.32 m along the direction of AD or in east-south direction.

Explanation: To find the correct answer, we need to know about the Displacement of a body in motion.

<h3>What is displacement of a body in motion?</h3>
  • The displacement is the shortest distance between initial and final positions of a body.
  • It's a vector quantity, and can positive, negative, or zero.
  • The magnitude of displacement is less than or equal to the distance travelled.
<h3>How to solve the problem?</h3>
  • At first, we can draw a diagram showing the motion of the body.
  • From the diagram, the displacement of the body will be equal to the distance between point A and D.
  • To solve this, we can use Pythagoras theorem.

AD=AC+CD\\AC^{2} =50^{2} +11^2\\AC=51.19 m\\Similarly,\\CD^2=35^2+9^2\\CD=36.13 m\\thus, \\AD=51.19+36.13=87.32 m

Thus, from the above calculations, we can conclude that, the displacement of the body will be equal to 87.32 m along the direction of AD or in east-south direction.

Learn more about the Displacement here:

brainly.com/question/28020108

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2 years ago
A particular lightbulb is designed to consume 40 W when operating on a car's 12-V DC electric power. If you supply that bulb wit
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40V because it will provide the same amount of power.
4 0
2 years ago
PLSSSSS HELP!!!!!!! ASAP!!!!! MARK BRAINLIEST!!!!
Ymorist [56]

Answer: I would say the answer is B.

Explanation: It looks and sounds the most correct.

5 0
3 years ago
A record player turntable initially rotating at 3313 rev/min is braked to a stop at a constant rotational acceleration. The turn
Rus_ich [418]

Answer:

(A) It will take 22 sec to come in rest

(b) Work done for coming in rest will be 0.2131 J              

Explanation:

We have given the player turntable initially rotating at speed of 33\frac{1}{3}rpm=33.333rpm=\frac{2\times 3.14\times 33.333}{60}=3.49rad/sec

Now speed is reduced by 75 %

So final speed \frac{3.49\times 75}{100}=2.6175rad/sec

Time t = 5.5 sec

From first equation of motion we know that '

\alpha =\frac{\omega -\omega _0}{t}=\frac{2.6175-3.49}{4}=-0.158rad/sec^2

(a) Now final velocity \omega =0rad/sec

So time t to come in rest  t=\frac{0-3.49}{-0.158}=22sec

(b) The work done in coming rest is given by

\frac{1}{2}I\left ( \omega ^2-\omega _0^2 \right )=\frac{1}{2}\times 0.035\times (0^2-3.49^2)=0.2131J

4 0
3 years ago
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