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Montano1993 [528]
3 years ago
6

How can you show that an electric current has a magnet affect​

Physics
1 answer:
lubasha [3.4K]3 years ago
5 0

Answer:

It is observed that when a compass is brought near a current carrying conductor the needle of compass gets deflected because of flow of electricity. This shows that electric current produces a magnetic effect.

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Which of the following steps to solve a problem is completed last?
Vesna [10]

Answer:

that would be analyzing data I believe

7 0
3 years ago
Read 2 more answers
A 150 g ball and a 240 g ball are connected by a 33-cm-long, massless, rigid rod. The balls rotate about their center of mass at
stira [4]

Answer:

v= 3.18 m/s

Explanation:

Given that

m= 150 g = 0.15 kg

M= 240 g = 0.24 kg

Angular speed ,ω = 150 rpm

The speed in rad/s

\omega =\dfrac{2\pi N}{60}

\omega =\dfrac{2\pi \times 150}{60}

ω = 15.7 rad/s

The distance of center of mass from 150 g

r=\dfrac{150\times 0+240\times 33}{150+240}\ cm

r= 20.30 cm

The speed of the mass 150 g

v= ω r

v= 20.30 x 15.7 cm/s

v= 318.71 cm/s

v= 3.18 m/s

6 0
3 years ago
How could a homework machine help students all around the world?
slamgirl [31]

Answer:

Hello There!!

Explanation:

The machine can help you alot and do all your homework while you rest and let the homework machine do it and get good grades because of it with no worries but if the machine does it then you won't learn how to do them.

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8 0
3 years ago
What is an example of frequency
emmasim [6.3K]

'Frequency' is a word that often confuses some people ... for no good reason.
It just means "frequent-ness" or "often-ness" ... how often something happens.

The SI unit of frequency is the Hertz (Hz).  Hz means 'per second'.
So  " 13 Hz "  means  13 per second.

Here are examples of frequency:

-- 780 kilohertz (on your AM radio dial)
-- 98.7 Megahertz (on your FM dial)
-- 5.8 Gigahertz
-- twice a day
-- three per week
-- every 6 months

6 0
4 years ago
Read 2 more answers
A proton is released from rest inside a region of constant, uniform electric field E1 pointing due North. 32.3 seconds after it
NARA [144]

Answer:

E₂ / E₁ = 521.64 / 5.95 =87.67

Explanation:

Let d be the distance covered inside electric field . Lt q be the magnitude of charge.

Force under field E₁ = q E₁

acceleration = qE₁/ m

d = 1/2 a t²

d = .5 ( qE₁ / m) x 32.3²

d = 521.64 ( qE₁ / m)

Similarly for return journey,

d = .5 x ( qE₂ / m) x 3.45²

d = 5.95x( qE₂ / m)

521.64 ( qE₁ / m) = 5.95x( qE₂ / m)

E₂ / E₁ = 521.64 / 5.95 =87.67

8 0
3 years ago
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