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Ber [7]
3 years ago
7

3. Study the position-time graph for a bicycle. Which statement is supported by the graph?

Physics
1 answer:
Ilya [14]3 years ago
4 0

Answer:

D. The bicycle has no motion.

Explanation:

The graph represents the position of the bike versus time.

From the graph, we see that the position of the bike is constant, at 3 metres  from the reference point, for the whole time: this means that the bike is not moving, so the correct option is

D. The bicycle has no motion.

From a position vs time graph, it is also possible to infer the velocity of the object, which is equal to the slope of the graph: in this case, the line is horizontal, so the slope is zero, which means that the bike's velocity is also zero.

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a pine raft (density = 373 kg/m^3) has a volume of 1.43 m^3. How much of the raft's volume is below the water line? Unit is m^3​
Slav-nsk [51]

Answer: 0.5334

Explanation:

i got it right on accellus :p

7 0
3 years ago
Define alpha and beta​
elena55 [62]

alpha is the excess return on an investment after adjusting for market related volatility and random fluctuations.

beta is a measure of volatility relative to a benchmark ,such as the S&P 500.

Explanation:

alpha and beta are two different parts of an equation used to explain the performance of stocks and investments funds. But in maths alpha and beta is the Greek alphabet

4 0
3 years ago
How many amps are there in the current of a circuit if the voltage source is 140v and the resistance is 2 ohms?
VLD [36.1K]
Voltage (V)= Current (I) * Resistance (R)
I=V/R=140/2=70A

Hope this helps!
7 0
3 years ago
A ray of light incident in air strikes a rectangular glass block of refractive index 1.50, at an angle of incidence of 45°. Calc
balandron [24]

Answer:

Approximately 28^{\circ}.

Explanation:

The refractive index of the air n_{\text{air}} is approximately 1.00.

Let n_\text{glass} denote the refractive index of the glass block, and let \theta _{\text{glass}} denote the angle of refraction in the glass. Let \theta_\text{air} denote the angle at which the light enters the glass block from the air.

By Snell's Law:

n_{\text{glass}} \, \sin(\theta_{\text{glass}}) = n_{\text{air}} \, \sin(\theta_{\text{air}}).

Rearrange the Snell's Law equation to obtain:

\begin{aligned} \sin(\theta_{\text{glass}}) &= \frac{n_{\text{air}} \, \sin(\theta_{\text{air}})}{n_{\text{glass}}} \\ &= \frac{(1.00)\, (\sin(45^{\circ}))}{1.50} \\ &\approx 0.471\end{aligned}.

Hence:

\begin{aligned} \theta_{\text{glass}} &= \arcsin (0.471) \approx 28^{\circ}\end{aligned}.

In other words, the angle of refraction in the glass would be approximately 28^{\circ}.

7 0
2 years ago
What would the velocity of an object be if it was on a 1.75m
JulijaS [17]

Answer:

T = 4 sec / 2 = 2 sec      period of revolution

S = 2 pi R = 2 * pi * 1.75 m = 11 m

V = S / T = 11 m / 2 sec = 5.5 m/s       speed of object

4 0
2 years ago
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