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Firdavs [7]
3 years ago
13

Evaluate the expression by using the given value of the variables.

Mathematics
1 answer:
yaroslaw [1]3 years ago
8 0
Y ÷ 2 • 4 – 10 ÷ x + 6 where <span>x = 5 and y = 16
</span>
Plug x=5 and y= 16 in the above expression:
16/ 2 *4 - 10/ 5 + 6
= 8 *4 - 2 + 6
= 32 -2 + 6
= 30 + 6
= 36.

c. 36 is the correct answer~

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A weightlifter holds a 1,700 N barbell 1 meter above the ground. One end of a 2-meter-long chain hangs from the center of the ba
masha68 [24]
In physics, work is equal to the product of force and distance, given that the direction of force is the same with the direction of the distance.

W = Fd

The total force is 
F = 1,700 N + 500 N = 2,200 N
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zimovet [89]

Answer:

8 cans

Step-by-step explanation:

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Zinaida [17]

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Step-by-step explanation: Gets x by itself.

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3 years ago
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loris [4]
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3 0
3 years ago
Read 2 more answers
Solve x'=5t(sqrt(x)) x(0)=1
LekaFEV [45]

Answer:

2\sqrt{x}=\frac{5t^2}{2}+2

Step-by-step explanation:

Given: \frac{\mathrm{d} x}{\mathrm{d} t}=5t\sqrt{x}\,,\, x(0)=1

Solution:

A differential equation is said to be separable if it can be written separately as  functions of two variables.

Given equation is separable.

We can write this equation as follows:

\frac{dx}{\sqrt{x}}=5t\,dt

On integrating both sides, we get

\int \frac{dx}{\sqrt{x}}=\int 5t\,dt

Formulae Used:

\int \frac{1}{\sqrt{x}}=2\sqrt{x}\,\,,\,\,\int t\,dt=\frac{t^2}{2}

So, we get solution as 2\sqrt{x}=\frac{5t^2}{2}+C

Applying condition: x(0) = 1, we get C=2

Therefore, 2\sqrt{x}=\frac{5t^2}{2}+2

8 0
3 years ago
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