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2 years ago

HELP THANKS 5y = 100 = ?

2 answers:

8 0

Y=20 as you have to divide 5 by 5 canceling out the 5 just leaving the y and then you have to divide 100 by 5 to equally complete the solution. Leaving y=20

Umnica [9.8K]2 years ago

5 0

Answer:

y=20

Step-by-step explanation:

5y = 100

Divide both sides by 5 (we can do this because of the division property of equality):

$\frac{5y}{5}=\frac{100}{5}$

$y=20$

y=20

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The equation x^2-9=0 has how many real solutions

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Tara is buying a shirt and a hat at the mall. The shirt cost $31.67 and if the hat cost $19.81. If she gave the sales clerk $100

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The correct answer to this question is $48.52

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Katherine begins a cruise to Bermuda on a Saturday. If the cruise lasts 18 days, on what day of the week will Katherine return?

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Answer:

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Select all the statements that are true for the following systems of equations

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Answer:

A. System C simplifies to 2x - 3y = 4 and 4x - y = 54 by dividing the second equation by three (3).

B. Systems A and C have the same solutions.

C. Systems A and B have different solutions.

Step-by-step explanation:

Given the following system of equations;

System A

2x - 3y = 4 .....equation 1

4x - y = 18 .......equation 2

We would solve the above equations using the elimination method;

Multiplying eqn 1 by 2;

2*(2x) - 2*(3y) = 4*2

4x - 6y = 8 ...... equation 3

Subtracting eqn 2 from eqn 3;

(4x - 4x) + (-6y - (-y)) = 8 - 18

0 + (-6y + y) = -10

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5y = 10

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y = 2

To find the value of x;

2x - 3y = 4

2x - 3(2) = 4

2x - 6 = 4

2x = 4 + 6

2x = 10

$x = \frac {10}{2}$

x = 5

Solutions (x, y) = (5, 2)

System B

3x - 4y = 5 ..... equation 1

y = 5x + 3 ..... equation 2

We would solve the equations using substitution method;

Substituting eqn 2 into eqn 1, we have;

3x - 4(5x + 3) = 5

3x - 20x - 12 = 5

-17x - 12 = 5

-17x = 12 + 5

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To find the value of y;

y = 5x + 3

y = 5(-1) + 3

y = -5 + 3

y = -2

Solutions (x, y) = (-1, -2)

System C

2x - 3y = 4 ..... equation 1

12x - 3y = 54 ...... equation 2

We would solve the above equations using the elimination method;

Subtracting eqn 2 from eqn 1;

(2x - 12x) + (-3y -(-3y)) = 4 - 54

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-10x + 0 = -50

-10x = -50

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x = 5

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2x - 3y = 4

2(5) - 3y = 4

10 - 3y = 4

3y = 10 - 4

3y = 6

$y = \frac {6}{3}$

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