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2 years ago

10

Write an explicit formula for an, the n

1 answer:

enyata [817]2 years ago

3 0

Answer:

$t_{n}$ =6n-2

Step-by-step explanation:

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Whats 1/3 of 1/2? thanks!

GuDViN [60]

Answer:

It's 1/6, hope this helps!

7 0

2 years ago

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Solve the following system of equations express your answer as an ordered pair in the format of (a,b) with no spaces between the

Alekssandra [29.7K]

Once we find what x and y is, that's where they intercept and we can write that as an ordered pair as (x,y) Now we need to find what y is. So let's put x into the original first equation 3x+4y=16 3(4)+4y=16 12+4y=16 ---Subtract 12 from both sides 4y=4 ---Divide both sides by 4 y=1 Alright, so our ordered pair is (4,1)

5 0

3 years ago

Bill paid $2.49 for 5 pounds of rice. What could be cost of 9 pounds

Nadya [2.5K]

Answer:

$\boxed{\sf Cost \ of \ 9 \ pounds \ rice =\$ 4.482}$

Given:

5 pounds rice cost $2.49

To Find:

Cost of 9 pounds rice

Step-by-step explanation:

5 pounds rice cost $2.49

1 pound rice will cost $ $\sf \frac{2.49}{5}$

So,

9 pounds rice cost = 1 pound rice cost × 9

= $ $\sf \frac{2.49}{5} \times 9$

= $0.498 × 9

= $4.482

3 0

3 years ago

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Which of the following correctly relates the measures of the measures of the measures of the diameter (d) and radius (r) of a ci

yaroslaw [1]

Hey!

Diameter is ½ of the radius. To find the radius when you have the diameter, divide by 2.

For example, if the diameter is 12, the the radius would be:

$12 \div 2 = 6$

<em>That means your answer will be C.</em>

$\framebox{Answer is C) r = d/2}$

4 0

3 years ago

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Given $m\geq 2$, denote by $b^{-1}$ the inverse of $b\pmod{m}$. That is, $b^{-1}$ is the residue for which $bb^{-1}\equiv 1\pmod

goblinko [34]

$(2+3)^{-1}\equiv5^{-1}\pmod7$ is the number <em>L</em> such that

$5L\equiv1\pmod7$

Consider the first 7 multiples of 5:

5, 10, 15, 20, 25, 30, 35

Taken mod 7, these are equivalent to

5, 3, 1, 6, 4, 2, 0

This tells us that 3 is the inverse of 5 mod 7, so <em>L</em> = 3.

Similarly, compute the inverses modulo 7 of 2 and 3:

$2a\equiv1\pmod7\implies a\equiv4\pmod7$

since 2*4 = 8, whose residue is 1 mod 7;

$3b\equiv1\pmod7\implies b\equiv5\pmod7$

which we got for free by finding the inverse of 5 earlier. So

$2^{-1}+3^{-1}\equiv4+5\equiv9\equiv2\pmod7$

and so <em>R</em> = 2.

Then <em>L</em> - <em>R</em> = 1.

6 0

3 years ago