Answer:
The value of k is 4
Explanation:
Solution
Given that:
k = integer
Input size = 500
The algorithm takes a run of = 16 seconds
Input size = 750
The algorithm takes a run of = 81 seconds
Now,
We have to determine the value of k
The equation is shown below:
(500)^k /16 = (750) ^k /81
Thus
(750/500)^ k = 81/16
= (3/2)^k
=(3/2)^ 4
k is = 4
Answer:
The answer is "Option c"
Explanation:
Plug and Play is a general term that is used to define gadgets operating with a computer network while connected to it. This technology allows the hardware to use automatically by adding it, and other option can be described as follows:
- In option a, This technology is used in monitoring the commercial vehicles system, which is why it's incorrect.
- In option b, It is wrong because It is used in Microsoft Windows, which increases the physical security.
- In option d, It describes the details about the hardware and switches to configure the device, that's why it is incorrect.
Answer:
With the use of data and their types the extent of how much data can be stored can get insanely large. types like doubles and longs allow for a range of values nearly incomprehensible in their size for storing user information, web pages, games ect. Using them essentially allows you to plan for the future of the size of whatever you're creating. On top of that, it allows for a preciseness not typically able to be reached without these types.
Answer:
C++
Explanation:
using namespace std;
class AbstractClass {
public:
virtual bool checkUpperCase(string inputString);
virtual string lowerToUppercase(string inputString);
virtual void stringToInt(string inputString);
};
class ConcreteClass: public AbstractClass {
public:
bool checkUpperCase(string inputString) {
bool isUpper = false;
for (int i=0; i < strlen(inputString); i++) {
if (isupper(inputString[i])) {
isUpper = true;
break;
}
return isUpper;
}
string lowerToUppercase(string inputString) {
for (int i=0; i < strlen(inputString); i++) {
putchar(toupper(inputString[i]));
}
return inputString;
}
void stringToInt(string inputString) {
int convertedInteger = stoi(inputString);
convertedInteger+=10;
cout<<convertedInteger<<endl;
}
};
int main() {
ConcreteClass cc;
return 0;
}
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