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pochemuha
4 years ago
7

The combination lock has three wheels, each numbered from 0 to 9. What is the probability that someone randomly guesses the corr

ect combination in one attempt?
Mathematics
1 answer:
Karolina [17]4 years ago
5 0
Since it is not mentioned in the problem, we will assume that repeating of number is allowed.
For the first wheel, you have 10 possible digits.
For the second wheel, you have 10 possible digits.
For the third wheel, you have 10 possible digits.
10 x 10 x 10 = 1000
The probability that someone randomly guesses the correct combination in his first attempt is 1/1000.

If this was without repeat, then 
10*9*8 = 720
The probability that someone randomly guesses the correct combination in his first attempt is 1/720.
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Answer:

3x - 4y + z = 1

Step-by-step explanation:

Given

Point\ 1 = (4,3,1)

Point\ 2 = (4,1,-7)

Perpendicular to 8x + 7y + 4z = 18

Required

Determine the plane equation

The general equation of a plane is:

a(x-x_1) + b(y - y_1) + c(z-z_1) = 0

For n =

(x_1,y_1,z_1) = (4,3,1)

(x_2,y_2,z_2) = (4,1,-7)

First, we need to determine parallel vector V_1

V_1 =

V_1 =

V_1 =

V_1 is parallel to the required plane

From the question, the required plane is perpendicular to 8x + 7y + 4z = 18

Next, we determine vector V_2

V_2 =

This implies that the required plane is parallel to V_2

Hence: V_1 and V_2 are parallel.

So, we can calculate the cross product V_1 * V_2

V_1 =

V_2 =

n = V_1 * V_2

V_1 * V_2 =\left[\begin{array}{ccc}i&j&k\\0&2&8\\8&7&4\end{array}\right]

The product is always of the form + - +

So:

V_1 * V_2 = i\left[\begin{array}{cc}2&8\\7&4\end{array}\right]  -j\left[\begin{array}{cc}0&8\\8&4\end{array}\right] +k\left[\begin{array}{cc}0&2\\8&7\end{array}\right]

Calculate the product

V_1 * V_2 = i(2*4- 8*7) - j(0*4- 8*8) + k(0*7 - 2 * 8)

V_1 * V_2 = i(8- 56) - j(0- 64) + k(0 - 16)

V_1 * V_2 = i(-48) - j(- 64) + k(- 16)

V_1 * V_2 = -48i +64j - 16k

So, the resulting vector, n is:

n =

Recall that:

n =

By comparison:

a = -48   b = 64   c = -16

Substitute these values in a(x-x_1) + b(y - y_1) + c(z-z_1) = 0

-48(x-x_1) + 64(y - y_1) -16(z-z_1) =0

Recall that:(x_1,y_1,z_1) = (4,3,1)

So, we have:

-48(x-4) + 64(y - 3) -16(z-1) =0

-48x + 192 + 64y -192 - 16z +16 = 0

Collect Like Terms

-48x + 64y - 16z = 0 - 192 + 192 - 16

-48x + 64y - 16z = -16

Divide through by -16

3x - 4y + z = 1

<em>Hence, the equation of the plane is</em>3x - 4y + z = 1<em></em>

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Answer:

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