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mestny [16]
3 years ago
10

Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the gi

ven equation.
(2-2) ;y=-x-2
A.y=-2x
B.y=2x
C.y=1/2x
D.y=-x
I have no idea how to work this out, I have a lot of other questions that are like this so just an answer isn't really going to help me out so much. Thanks for all help given!
Mathematics
1 answer:
Marrrta [24]3 years ago
5 0
 y = x - 2.....the slope here is 1. A parallel line will have the same slope

y = mx + b
slope(m) = 1
(2,-2)...x = 2 and y = -2
now we sub and find b, the y int
-2 = 1(2) + b
-2 = 2 + b
-2 - 2 = b
-4 = b

so ur parallel line is : y = x - 4

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The expression which is equivalent to the given expression as in the task content is; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power.

<h3>What is the expression which is equivalent to the given expression?</h3>

According to the task content, it follows that the expression given is;

(1.5⁵/0.7⁴)³

= 1.5^(3×5) /0.7^(4×3)

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Hence, the expression which is equivalent is; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power.

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