PLEASE HELP ASAP! ITS DUE SOON, ILL GIVE BRAINLIEST PLEASE EXPLAIN YOUR ANSWER

Fill in the blanks to complete the area model to solve 6.60 divided by 15 is the same as _ x ? = _ 6.60 = _ hundredths

storchak [24]

Answer:

$15 x = 6.60$

$x = 44\ hundredths$

Step-by-step explanation:

Given

$\frac{6.60}{15}$

Required

Complete the model

[ ] x = 6.60

x = _ hundredths

$\frac{6.60}{15}$

Equate to x

$x = \frac{6.60}{15}$

Multiply both sides by 15

$15 * x = \frac{6.60}{15} * 15$

$15 * x = 6.60$

$15 x = 6.60$

So, we have:

[ ] x = 6.60 =====> $15 x = 6.60$

Recall that:

$x = \frac{6.60}{15}$

$x = 0.44$

This implies that:

$x = 44\ hundredths$

Hence:

x = _ hundredths =====> $x = 44\ hundredths$

3 0

2 years ago

Need help test is due 3/10/18

Kazeer [188]

I believe <span>angle 1 is 115° </span>

8 0

3 years ago

Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr$
$=\dfrac\pi2$

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
$=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du$
$=-2\pi$

So, the flux over the paraboloid alone is

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

3 years ago

D'Quans grandmother made a quilt for his bed.the quilt is 2.44 meters long and 1.83 meters wide.what is the area of the quilt in

Ede4ka [16]

The best way to do this is to first change each of the measurements into feet and then calculate the area:

2.44m = 8.01ft
1.83m = 6.00ft

When multiplied together (to give the area) we get:

8.01*6.00 = 48.1ft²

5 0

3 years ago

Read 2 more answers

A man flies a kite at a height of 15 ft. The wind is carrying the kite horizontally from the man at a rate of 5 ft./s. How fast

Misha Larkins [42]

Answer:

4.4 ft/s

Step-by-step explanation:

Height = 15ft

Rate= 5 ft/s

Distance from the man to the kite= 32ft

dh/dt = 5 ft/s

h = √32^2 - 15^2

h = √ 1025 - 225

h = √800

h = 28.28ft

D = √15^2 + h^2

dD/dt = 1/2(15^2 + h^2)^-1/2 (2h) dh/dt

= h(225 + h^2)^-1/2 dh/dt

= (h / √225 + h^2)5

= (28.28 / √225 + 28.28^2)5

= (28.28 / √1024.7584)5

= (28.28/32)5

= 0.88*5

= 4.4 ft/s

3 0

3 years ago