3,4,7 just plug the x into the equation
<YZW = <X = 63
hope it helps
Answer:
![r ^{2} = (x-4)^2 + (y+1)^{2}](https://tex.z-dn.net/?f=r%20%5E%7B2%7D%20%3D%20%28x-4%29%5E2%20%2B%20%28y%2B1%29%5E%7B2%7D)
Given:
endpoints at (-1, 6) and (9, -8)
Solve for:
the standard equation of a circle having endpoints of a diameter at (-1, 6) and (9,-8).
Step-by-step explanation:
![d=\sqrt{(x_{2} -x_{1})^2+(y_{2} -y_{1})^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_%7B2%7D%20-x_%7B1%7D%29%5E2%2B%28y_%7B2%7D%20-y_%7B1%7D%29%5E2%7D)
![d=\sqrt{(9-(-1))^2+(-8-6)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%289-%28-1%29%29%5E2%2B%28-8-6%29%5E2%7D)
![d=\sqrt{10^2+-14^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B10%5E2%2B-14%5E2%7D)
![d=\sqrt{100+196}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B100%2B196%7D)
![d=\sqrt{296}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B296%7D)
![d=2\sqrt{74}](https://tex.z-dn.net/?f=d%3D2%5Csqrt%7B74%7D)
![r=\frac{d}{2}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bd%7D%7B2%7D)
![r=\frac{2\sqrt{74} }{2}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B2%5Csqrt%7B74%7D%20%7D%7B2%7D)
![r=\sqrt{74}](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B74%7D)
![Center = (\frac{x_{1}+x_{2} }{2} ,\frac{y_{1}+y_{2} }{2})](https://tex.z-dn.net/?f=Center%20%3D%20%28%5Cfrac%7Bx_%7B1%7D%2Bx_%7B2%7D%20%7D%7B2%7D%20%2C%5Cfrac%7By_%7B1%7D%2By_%7B2%7D%20%7D%7B2%7D%29)
![= (\frac{-1+9}{2}, \frac{6+(-8)}{2} )](https://tex.z-dn.net/?f=%3D%20%28%5Cfrac%7B-1%2B9%7D%7B2%7D%2C%20%5Cfrac%7B6%2B%28-8%29%7D%7B2%7D%20%29)
![=(4, -1)](https://tex.z-dn.net/?f=%3D%284%2C%20-1%29)
![Center = (4,-1) \\and\\r = \sqrt{74}](https://tex.z-dn.net/?f=Center%20%3D%20%284%2C-1%29%20%5C%5Cand%5C%5Cr%20%3D%20%5Csqrt%7B74%7D)
Equation:
![(\sqrt{74}) ^{2} = (x-4)^2 + (y+1)^{2}](https://tex.z-dn.net/?f=%28%5Csqrt%7B74%7D%29%20%5E%7B2%7D%20%3D%20%28x-4%29%5E2%20%2B%20%28y%2B1%29%5E%7B2%7D)
![r ^{2} = (x-4)^2 + (y+1)^{2}](https://tex.z-dn.net/?f=r%20%5E%7B2%7D%20%3D%20%28x-4%29%5E2%20%2B%20%28y%2B1%29%5E%7B2%7D)
*This took forever so I hoped it helped lol*
Answer:
it is 15
Step-by-step explanation: