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2 years ago

Is 3 kL greater or less than 30,000 L? Please help

Mathematics

2 answers:

OverLord2011 [107]2 years ago

7 0

No! 30,000 liters is way greater

prohojiy [21]2 years ago

7 0

Nope 30,000 litters i way more greater than 3 klg

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last month Tara work 16.5 hours the first week 19 hours the second week 23 hours the third week 15.75 hours the fourth week she

STatiana [176]

The number of hours, h, Tara plans to work this month are greater than 16.5 + 19 + 23 + 15.75. Therefore, h > 16.5 + 19 + 23 + 15.75.

h > 74.25

7 0

3 years ago

Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball

Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and $51\frac{1}{3}$ yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from $51\frac{1}{3}$ yards.

$\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}$

Let us have a common denominator.

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}$

$\text{1 yard}=3\text{ feet}$

$\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}$

$\frac{28}{3}\text{ yards}=28\text{ feet}$

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

7 0

3 years ago

If y = 12 when x = 3, find x when y = 6.

kari74 [83]

Answer:

X would equal 1.5

Step-by-step explanation:

if 12 divided by 2 equals 6, then you have to find what's half of 3 which is 1.5

7 0

2 years ago

Read 2 more answers

F(x)=x^2+4x and g(x)= 2x+2, find f(5)+ g(6)

Lubov Fominskaja [6]

F(5) = 5² +4*5=25+20 = 45
g(6) = 2*6 +2 =12+2=14

f(5) + g(6)= 45 +14 =59

3 0

2 years ago

If a family has 6 children, in how many ways could the parents have 3 boys and 3 girls?

Jlenok [28]

The parents could have 3 boys and 3 girls in 400 ways

<h3>How to determine the number of ways?</h3>

The given parameters are

Children, n = 6

Boys, r = 3

Girls, r =3

The number of combination is:

$Ways = ^nC_{r1} *^nC_{r2}$

So, we have:

$Ways = ^6C_3 *^6C_3$

Apply the combination formula

$Ways = \frac{6!}{3!3!} *\frac{6!}{3!3!}$

This gives

Ways = 400

Hence, the parents could have 3 boys and 3 girls in 400 ways