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gregori [183]
3 years ago
6

joe is playing a game with a regular die. If the number that turns up is even he will gain 5 times the number that comes up. If

it is odd, he will lose 10 times the number that comes up. He tosses a 3
Mathematics
1 answer:
vladimir1956 [14]3 years ago
5 0

Answer:

he lost 30 points.

since he rolled an odd number, he will lose 10 times the number he rolled. he rolled 3, which means he lost 30 points. you get that by multiplying 3 and 10.

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Somebody help me out please
quester [9]

Answer:

the correct answer is d.

Step-by-step explanation:

i hope this helps :)

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2 years ago
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What is the output of the function f(p) = 3p – 2 when the input is 2?
vovikov84 [41]
Just plug in 2 for p. 3*2 - 2 = 6-2 = 4
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3 years ago
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If correct I will give brainly​
Marizza181 [45]

Answer:

B

Step-by-step explanation:

all you need to do is switch the x with 12

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3 years ago
To rationalize the denominator of 2/square 13+ squared 11 , you should multiply the expression by which fraction?
eimsori [14]

<u><em>Answer:</em></u>

You should multiply the expression by \frac{\sqrt{13}-\sqrt{11}}{\sqrt{13}-\sqrt{11}}

<u><em>Explanation:</em></u>

To rationalize any expression, you must multiply it by its conjugate. A conjugate is defined as a similar expression to the original one but with an opposite sign

<u>This means that:</u>

The conjugate of a + b would be a -  b

Now, the given expression is \frac{2}{\sqrt{13}+\sqrt{11}}

<u>Consider the denominator:</u>

From the above, we can conclude that the conjugate of \sqrt{13}+\sqrt{11} is \sqrt{13}-\sqrt{11}

<u>And, remember that</u> we need to keep the value of the expression unchanged. This means that we must multiply both the numerator and the denominator by the same value

<u>Therefore:</u>

You should multiply the expression by \frac{\sqrt{13}-\sqrt{11}}{\sqrt{13}-\sqrt{11}} in order to rationalize the denominator

Hope this helps :)

5 0
3 years ago
Read 2 more answers
If PQ=8 and Q lies at -13 where could P be located?
choli [55]

Answer:

In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).

Step-by-step explanation:

There is really no need to use any quadratics or roots.

( Consider the same problem on the plain number line first.  )

How do you find the number between 2 and 5 which is twice as far from 2 as from 5?

You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get

4=2+23(5−2)

It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then

R=P+23(Q−P)

so in your case we get

R=(0,−1)+23(3,3)=(2,1)

Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)

Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get

s=a+b=2b+b=3b

⇔b=13s⇒a=23s

7 0
3 years ago
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