All categories

3 years ago

What is the product of 3x4 y2 and 2xy3?

1 answer:

5 0

3x $3x^{4} y^{2} (2x y^{3} )$
$6x^{5} y^{5}$
When multiplying, power is added. When divide, it is subtracted.
The for answer of this product is
$6x^{5} y^{5}$

You might be interested in

If you bought your car 5 years ago for $15,000 and today you can sell for $7000, what was it's rate of depreciation? Round to tw

serg [7]

Answer : The rate of depreciation is, $16000

Step-by-step explanation :

Formula used to calculate the rate of depreciation is:

$\text{Depreciation rate}=\frac{\text{Purchase price of asset }+\text{ Salvage value}}{\text{Estimate life of asset}}$

Given:

Purchase price of asset = $15000

Salvage value = $7000

Estimate life asset = 3 years

Now put all the given values in the above formula, we get:

$\text{Depreciation rate}=\frac{15000+7000}{5}$

Deprecation rate = $16000

Therefore, the rate of depreciation is, $16000

5 0

3 years ago

Pleaseeeeeeeee helppp

Stolb23 [73]

2(x-1)=42
2x-2=42
2x=44
X=22

8 0

3 years ago

The faces of a tetrahedron die are numbered 1 to 4. if each of the 4 sides is equally likely to land down, what is the probabili

Hoochie [10]

The probability distribution for the face landing down = 4/15

<h3>What is the probability?</h3>

The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a claim to be true. A number between 0 and 1 is the probability of an event, where, broadly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.

<h3>According to the given information:</h3>

If we assign 1 probability x

then 2 has probability 1/2 x.

Similarly,

then 3 has probability = 1/2((1/2)*x) = (1/4)*x

then 4 has probability = 1/2((1/4)*x) = (1/8)*x

These probabilities need to sum to 1.

Hence:

$x+\frac{1}{2} x+\frac{1}{4} x+\frac{1}{8} x=1$

or equivalently

(15/8)*x = 1

x = 8/15

the probability distribution for the face landing down = (1/2)*(8/15)

= 8/30

= 4/15

To know more about probability visit:

brainly.com/question/1581057

#SPJ4

I understand that the question you are looking for is:

A tetrahedral die has four faces, numbered 1-4. If the die is weighted in such a way that each number is twice as likely to land facing down as the next number (1 twice as likely as 2, 2 twice as likely as 3, and so on) what is the probability distribution for the face landing down?

7 0

1 year ago

Need help simplifying this

diamong [38]

The simplified answer is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$ .

<u>Step-by-step explanation:</u>

$$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term $(\frac{3x+y}{3x+y})$ and 2nd term by $(\frac{z+2x}{z+2x})$

= $\frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= $\frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}$