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hichkok12 [17]
3 years ago
5

Which figures are polygons?

Mathematics
2 answers:
castortr0y [4]3 years ago
8 0
Your answer would be A, B, and C.
Harrizon [31]3 years ago
3 0
A,a, b, c, I think will be your correct answer
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Use properties to find 4 times 23 times 25
erastova [34]
The answer to the problem is 2300
8 0
3 years ago
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PLEASE HELP 80 PTS.<br> Math stuff...
White raven [17]

Answer:

a) m∠6 = 55 and m∠8= 55 - 20 --> m∠8= 35     x = 55

b) m∠7 = 40 and m∠9 = 140                                x = 40

c) m∠8 = 46 and m∠7 = 46                                  x = 18

d) m∠6 = 63 and m∠7 = 27                                  x = 9

(just like the note says at the top each one is a different problem hence the different answer or each angle even if its the same one)

Step-by-step explanation:

I've attached my work

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Please give me feedback on my repsomse by commenting,

any way i can improve showing my work?

Hope it helps, let me know if you have questions !

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6 0
1 year ago
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Today a typical family of four spends $897.20/ month for food. If inflation occurs at the rate of 3%/ year over the next 6 years
mezya [45]

Answer:

  1071.30 per month

Step-by-step explanation:

The multiplier each year is 1 + .03 = 1.03. After 6 years, the cost has been multiplied by that factor 6 times, so has been multiplied by 1.03⁶ ≈ 1.194052.

  $897.20 × 1.194052 ≈ $1071.30

6 0
3 years ago
Can anyone please help me with this question?
adelina 88 [10]

Answer:

15 cm

Step-by-step explanation:

A= base x height

\frac{1500cm^{3} }{100 {cm}^{2} }  \\  = 15cm

4 0
2 years ago
John had a bag of marbles as shown below.
Montano1993 [528]

Answer:

\sf A) \quad \dfrac{9}{100}

Step-by-step explanation:

Given:

  • 3 green marbles
  • 4 blue marbles
  • 2 red marbles
  • 1 yellow marble

Total number of marbles = 3 + 4 + 2 + 1 = 10

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

Probability of selecting a green marble on first pick:

\implies \sf P(green\:marble)=\dfrac{3}{10}

Probability of selecting a green marble on second pick:

\implies \sf P(green\:marble)=\dfrac{3}{10}

(as the 1st pick was replaced)

Therefore,

\implies \textsf{P(green marble) and P(green marble)} \sf =\dfrac{3}{10} \times \dfrac{3}{10}=\dfrac{9}{100}

7 0
2 years ago
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