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grandymaker [24]
3 years ago
10

Can someone please help me with this. Everyone is giving me the wrong answers!

Mathematics
2 answers:
swat323 years ago
5 0

check the picture below.


the outside line touching the circle, the 13.5 one, we don't have enough info to say is a secant, like the 8.45 one, so the 13.5 is a tangent line, which is touching the radius chord, and the point of tangency is always a right angle.

Sonja [21]3 years ago
4 0

Assuming that the side of the triangle marked 13.5 is tangent to the circle, the there's a right angle where the radius meets the tangent segment. The triangle is then a right triangle and the Pythagorean Theorem applies.



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Answer:

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Step-by-step explanation:

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What is the answer to 8=56, 7=42, 6=30, 5=20, 3=?
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The hypotenuese of an isosceles right triangle is 13 inches. The midpoints of its sides are connected to form an inscribed trian
Georgia [21]

Answer:

The Sum of the areas of theses triangles is 169/3.

Step-by-step explanation:

Consider the provided information.

The hypotenuse of an isosceles right triangle is 13 inches.

Therefore,

x^2+x^2=169\\2x^2=169\\x=\frac{13}{\sqrt{2} }

Then the area of isosceles right triangle will be: A=\frac{1}{2} x^2

Therefore the area is: A=\frac{169}{4}

It is given that sum of the area of these triangles if this process is continued infinitely.

We can find the sum of the area using infinite geometric series formula.

S=\frac{a}{1-r}

Substitute a=\frac{169}{4} \ and\ r=\frac{1}{4} in above formula.

S=\frac{\frac{169}{4}}{1-\frac{1}{4}}

S=\frac{\frac{169}{4}}{\frac{3}{4}}

S=\frac{169}{3}

Hence, the Sum of the areas of theses triangles is 169/3.

7 0
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3 years ago
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