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Kruka [31]
3 years ago
7

The nth term of a sequence is n-4

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
4 0

Answer:

Step-by-step explanation:

nth term = n - 4

A) 1st term = 1 - 4 = -3

2nd term = 2 - 4 = -2

3rd term = 3 - 4 = -1

First three terms are:  -3, -2, -1

b) tenth term = 10 - 4 = 6

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Leona [35]
Just divide the y numbers by the x numbers and that's it
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3 years ago
What is the length of chord An in Oo below?
Anika [276]

Answer:

12 units

Step-by-step explanation:

In\: \odot O,

  • chords \overline{ML} and \overline{AN} are equidistant (7.2 units) from the center of the circle O.
  • Measures of the chords equidistant from the center of the circle are equal.
  • \therefore m(chord\:\overline{AN}) =m(chord\:\overline{ML})
  • \because m(chord\:\overline{ML}) = 12\: units
  • \therefore m(chord\:\overline{AN}) = 12\: units
4 0
3 years ago
Chase is comparing music subscription price . a 12 month with all ears cost $91.80 and a subscription with press play cost $19.3
WINSTONCH [101]

Answer:

its press play

Step-by-step explanation:

8 0
3 years ago
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The graph of f is given in the figure to the right. Let ​A(x)equals=Integral from 0 to x f left parenthesis t right parenthesis
Tpy6a [65]

Answer:

A(4)=-4\pi

A(8)=-4\pi +8

A(12)=-4\pi +16

A(14)=-4\pi +15

Step-by-step explanation:

we are given

A(x)=\int\limits^x_0 f{x} \, dx

Calculation of A(4):

we can plug x=4

A(4)=\int\limits^4_0 f{x} \, dx

Since, this curve is below x-axis

so, the value of integral must be negative

and it is quarter of circle

so, we can find area of quarter circle

radius =4

A(4)=-\frac{1}{4}\times \pi \times (4)^2

A(4)=-4\pi

Calculation of A(8):

we can plug x=8

A(8)=\int\limits^8_0 f{x} \, dx

we can break into two parts

A(8)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx

now, we can find area and then combine them

A(8)=-4\pi +\frac{1}{2}\times 4\times 4

A(8)=-4\pi +8

Calculation of A(12):

we can plug x=12

A(12)=\int\limits^12_0 f{x} \, dx

we can break into two parts

A(12)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx+\int\limits^12_8 f{x} \, dx

now, we can find area and then combine them

A(12)=-4\pi +\frac{1}{2}\times 8\times 4

A(12)=-4\pi +16

Calculation of A(14):

we can plug x=14

A(14)=\int\limits^14_0 f{x} \, dx

we can break into two parts

A(14)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx+\int\limits^12_8 f{x} \, dx+\int\limits^14_12 f{x} \, dx

now, we can find area and then combine them

A(14)=-4\pi +\frac{1}{2}\times 8\times 4-\frac{1}{2}\times 1\times 2

A(14)=-4\pi +16-1

A(14)=-4\pi +15

8 0
3 years ago
Which is the graph of the linear inequality x – 2y > –6?
Zina [86]

Answer:

On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 4, 2) and (4, 4). Everything below and to the right of the line is shaded.

Step-by-step explanation:

The first step is writing in the general form of the first order equation

y = f(x) or y > f(x) or y < f(x)

And

f(x) = ax + b

In which a is the slope.

We have that:

x - 2y > -6

-2y > -6 - x

When multiplying by -1, the signal changes, from > to <

2y < x + 6

y < 0.5x + 3

The slope is positive, since 0.5 is positive.

Since it is y lesser than, it is everything below and to the right of f(x) is painted.

The line is dashed because this is just lesser, not lesser or equal.

The correct answer is:

On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 4, 2) and (4, 4). Everything below and to the right of the line is shaded.

8 0
3 years ago
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