No sir. You NEED to do your OWN work, stop asking for help you delinquent
Answer:
Anika is correct
Step-by-step explanation:
* Lets revise the rules of reflection and rotation
- If point (x , y) reflected across the x-axis then its image is (x , -y)
- If point (x , y) rotated about the origin by angle 270° clock wise then
its image is (-y , x)
* Lets check the vertices of the two triangles
- The vertices of Δ ABC are:
# A (-7 , 2)
# B (-3 , 6)
# C (-2 , 1)
- The vertices of Δ PRQ
# P (-7 , -2)
# R (-3 , -6)
# Q (-2 , -1)
* By comparing between the vertices of the two triangles
∵ Each y-coordinates of Δ PRQ has opposite sign of each
y-coordinates of Δ ABC
∵ All x-coordinates of Δ PRQ are the same with x-coordinates of
Δ ABC
- That means Δ PRQ is the image of Δ ABC after reflection across
the x-axis
∵ Reflection doesn't change the shape and the size of the figure
∴ Δ ABC and Δ PRQ have same size (equal sides and equal angles)
∴ Δ ABC is congruent to Δ PRQ
* Anika is correct
Answer:
Step-by-step explanation:
product: -18x4 + 15x2 - 15x
the simplification just ends up being the original equation.
Since the two angles form a linear pair, the sum of their
angles is equal to 180°. The condition given in the problem is that one angle is
one-third of the other angle, or simply speaking, one angle is three times more
than the other angle. We find the values of the angles by dividing the sum of
the angles by 4 and assigning 3 and 1 times the dividend.
180°/4 = 45°
By obtaining the dividend, we obtain the values of the
angles to be 45° and 135°.