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2 years ago

❗️Help needed please ❗️

Mathematics

2 answers:

elixir [45]2 years ago

7 0

Answer:

prove it by S.S.S axiom bro

Step-by-step explanation:

statement reason

1.in triangle ADB and ADC

a. AB=AC a.given

b.BD=CD b. radii of same circle

c. AD=AD c. common side

2. ∵triangle ADB is congurent to 2. by S.S.S axiom

ADC

cupoosta [38]2 years ago

5 0

Answer:

AD cuts BC at I => I is the midpoint of BC => BI = CI

ΔAIB and ΔAIC have:

AB = AC

BI = CI

m∠ABC = m∠ACB ( because ΔABC is a isosceles triangle)

=> ΔAIB ≅ ΔAIC (sas)

=> m∠BAD = m∠CAD

ΔADB and ΔADC have:

m∠BAD = m∠CAD

AB = AC

AD is the common edge

=> ΔADB ≅ ΔADC (sas)

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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2 years ago

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dedylja [7]

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3 years ago

What must you do to the first inequality to get to the second inequality? A. N 4 <5;n<20 b. − n 4 <5;n>−20 A. A. Add

adell [148]

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