It would be
2x3xnxn
N has a 1 in front of it it's just not shown
So
2x3x1nx1n then you'd at as much as possible
5x2n
Answer:
If
whenever
f is <em>increasing</em> on I.
If
whenever
f is <em>decreasing</em> on I.
Step-by-step explanation:
These are definitions for real-valued functions f:I→R. To help you remember the definitions, you can interpret them in the following way:
When you choose any two numbers
on I and compare their image under f, the following can happen.
. Because x2 is bigger than x1, you can think of f also becoming bigger, that is, f is increasing. The bigger the number x2, the bigger f becomes.
. The bigger the number x2, the smaller f becomes so f is "going down", that is, f is decreasing.
Note that this must hold for ALL choices of x1, x2. There exist many functions that are neither increasing nor decreasing, but usually some definition applies for continuous functions on a small enough interval I.
Answer:
15 dollars
Step-by-step explanation:
We can write a ratio to solve
6 cones 9 cones
------------ = --------------
10 dollars x dollars
Using cross products
6*x = 10 *9
6x = 90
Divide each side by 6
6x/6 = 90/6
x = 15
To what ???? Was there supposed to be a picture?