8m(4+7p). (The greatest common factor is 8.).
Answer:
1. ![22.22\°C](https://tex.z-dn.net/?f=22.22%5C%C2%B0C)
2. ![212.00\°F](https://tex.z-dn.net/?f=212.00%5C%C2%B0F)
Step-by-step explanation:
1. The exercise provides the function for the conversion from Degrees Fahrenheit to Degree Celsius:
Therefore, in order to find the equivalent conversion of
to Celsius, we need to substitute
into the function. Then, we get:
2. We also have this function for the conversion from Degree Celsius to Degrees Fahrenheit:
![T(\°F) = (T(\°C) *\frac{9}{5})+32](https://tex.z-dn.net/?f=T%28%5C%C2%B0F%29%20%3D%20%28T%28%5C%C2%B0C%29%20%2A%5Cfrac%7B9%7D%7B5%7D%29%2B32)
Then, we need to substitute
into the function in order to find the equivalent conversion of
to Fahrenheit. Then, we get:
![T(\°F) = (100 *\frac{9}{5})+32\\\\T(\°F)=212.00](https://tex.z-dn.net/?f=T%28%5C%C2%B0F%29%20%3D%20%28100%20%2A%5Cfrac%7B9%7D%7B5%7D%29%2B32%5C%5C%5C%5CT%28%5C%C2%B0F%29%3D212.00)
Given:
U be the set of all books, N the set of all novels, and H be the set of all hardcover books.
To find:
The description for the sets
and
in words.
Solution:
We have,
U = The set of all books
N = The set of all novels
H = The set of all hardcover books.
We know that
means common elements of set N and set H.
Therefore,
is set of all books that are both novels and hardcover books.
We know that
is the set of elements of universal set except the elements of set H.
Therefore,
is the set of all books that are not hardcover books.
Answer:
I think that statement is false