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Nastasia [14]
3 years ago
13

Identify the following series as arithmetic, geometric, both, or neither.

Mathematics
2 answers:
morpeh [17]3 years ago
8 0

Answer:

Option 2 - Geometric series  

Step-by-step explanation:

Given : Series 3a+3a^2+3a^3+.....+3a^n

To identify : The following series as arithmetic, geometric, both, or neither.

Solution :

According to the series,

3a+3a^2+3a^3+.....+3a^n

If we take 3 common,

=3(a+a^2+a^3+.....+a^n)

the above series make is a geometric series as 3 is a constant.

Geometric series is \sum_k a_k where ratio of two terms is \frac{a_{k+1}}{a_k}

In the above given series, the common ratio is a.

As the series satisfy all conditions of geometric series.

Therefore, Option 2 is correct.

pychu [463]3 years ago
3 0
The expression <span>3a + 3a² + 3a³ + . . . + 3an is a geometric expression, because 3 is constant. </span>
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Step-by-step explanation:

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The train travels 580 miles in 4 hours. The train travels at a constant rate. At this rate, how many hours will it take the trai
Mandarinka [93]

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8 0
3 years ago
Y = -2x - 4<br> y = 4x + 2
adoni [48]

The value of x and y in the given equation  is determined -1 and -2 respectively.

<h3>Value of x and y</h3>

The value of x and y can be determined by solving the two equations simultaneously.

y = -2x - 4  ----- (1)

y = 4x + 2   ----- (2)

solve (1) and (2) together

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6 0
2 years ago
Line p is parallel to line q. if the measure of angle 3 is 54°, what is the measure of angle 6
Free_Kalibri [48]

Answer:

m\angle 6=54^o

Step-by-step explanation:

The complete question in the attached figure

we know that

When two lines are crossed by another line (transversal), a pair of angles on the inner side of each of those two lines but on opposite sides of the transversal, are called <em><u>Alternate Interior Angles</u></em>.

When the two lines being crossed are Parallel Lines the Alternate Interior Angles are congruent

In this problem

m\angle 6=m\angle 3 ---> by alternate interior angles

we have

m\angle 3=54^o

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m\angle 6=54^o

7 0
3 years ago
A triangle has angles that measure 30o, 60o, and 90o. The hypotenuse of the triangle measures 10 inches. Which is the best estim
OverLord2011 [107]

Given: In Δ ABC, ∠B =90° , ∠C = 30° , ∠A = 60° and Hypotenuse AC = 10 inches

It has been described in the attachment.

Now, we shall calculate side AB and BC by using Trigonometric Ratios.

Sin 30° = AB / AC

or,     AB = 10 × Sin 30° = 10 × 0.5 = 5 inches

And,  Cos 30° = CB / AC

or,               CB =  10 × Cos 30° = 10 × 0.866 = 8.66 inches

Now, we shall calculate the perimeter of the given triangle

Perimeter of the triangle = AB + BC + CA

or,                                      = (5.0 + 8.66 + 10.0 ) inches

or,                                      = 23.66 inches ≈ 23.7 inches

Hence, the best estimate for the perimeter of the triangle ( round to the nearest tenth will be 23.7 inches.

8 0
3 years ago
Read 2 more answers
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