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3 years ago

Find the surface area please help

Mathematics

1 answer:

aleksklad [387]3 years ago

4 0

Answer:

your answer would be 60.

Step-by-step explanation:

when finding surface area, you have to multiply all your values to get the answer.

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What is the measure of arc EF in circle H?<br> O 41°<br> O 50°<br> O 114<br> O 1730

timurjin [86]

Answer:

The measure of arc EF = 41°

Step-by-step explanation:

Given:

Arc DE = 73°

$\angle FED=123\°$

Now, we know from central angle theorem that the measure of central angle by an arc is twice that of the angle made by the same arc at the circumference. Therefore,

$\textrm{Major Arc DGF}=2\times \angle FED\\\textrm{Major Arc DGF}=2\times 123\\\textrm{Major Arc DGF}=246\°$

Now, we know that sum of all arcs on a circle is equal to 360°.

Therefore, arc DGF + arc DE + arc EF = 360°

$246+73+arc\ EF=360\\319+arc\ EF=360\\arc\ EF=360-319=41\°$

Therefore, the measure of the arc EF is 41°.

7 0

3 years ago

Read 2 more answers

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Sedbober [7]

Answer:

E ( 1 , -1 ) is in quadrant IV

6 0

2 years ago

1/3x + 4 = 10 what is x

nydimaria [60]

Answer:

X = -13/10

Step-by-step explanation:

5 0

3 years ago

The area of a square is 81 centimeters find the length of the length find the diagonal

EleoNora [17]

Length = √area = √81 = 9

diagonal = √2 * side = √2*9 = 9√2

5 0

3 years ago

Assume that a procedure yields a binomial distribution with a trial repeated n = 5 times. Use some form of technology to find th

Digiron [165]

Answer:

$P(X = 0) = 0.0263$

$P(X = 1) = 0.1407$

$P(X = 2) = 0.3012$

$P(X = 3) = 0.3224$

$P(X = 4) = 0.1725$

$P(X = 5) = 0.0369$

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 5, p = 0.517$

Distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.517)^{0}.(0.483)^{5} = 0.0263$

$P(X = 1) = C_{5,1}.(0.517)^{1}.(0.483)^{4} = 0.1407$

$P(X = 2) = C_{5,2}.(0.517)^{2}.(0.483)^{3} = 0.3012$

$P(X = 3) = C_{5,3}.(0.517)^{3}.(0.483)^{2} = 0.3224$

$P(X = 4) = C_{5,4}.(0.517)^{4}.(0.483)^{1} = 0.1725$

$P(X = 5) = C_{5,5}.(0.517)^{5}.(0.483)^{0} = 0.0369$

6 0

3 years ago