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siniylev [52]
3 years ago
11

Consider circle C with radius 5 cm and a central angle measure of 60°. What fraction of the whole circle is arc RS?

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0

Answer:

There are a total of 360° in any given circle, so an arc swept out by 60° of that 360° would make up 60/360 = 1/6 of the circle's circumference.

The formal for the circumference of a circle comes out of the definition of one of the most famous constants in mathematics: π. π is defined as the ratio between a circle's circumference and its diameter, or:

From this definition, we can multiply both sides of the equation by d to obtain

or, circumference is π times the diameter. To find the diameter, we just need to double the radius, giving us 5 * 2 = 10cm. Usually you'll see π approximated as 3.14, which is likely what they want you to use here. Using that approximation, we find the circumference to be 3.14 * 10 = 31.4 cm.

Finally, to get the length of that arc, we just need to take 1/6 of the circumference (since the arc sweeps out 1/6 of the circle), giving us 31.4 * 1/6 ≈ 5.2 cm.

Step-by-step explanation:

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Negative Correlation.

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We see that the overall trend is going downward, though it is a bit difficult to spot. We are able to draw a best line of fit, and the slope would be negative.

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4 years ago
Find the measure of angle 2 if the measure of angle 8 is 40<br> degrees.
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2=40°

Step-by-step explanation:

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3 years ago
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Evaluate each function following the specification.
telo118 [61]

Answer:

#3 a. g(-1) = 2, g(0) = 3, and g(1) = 2

b. No restrictions for all real numbers

\#4 \  a. \ h(-1) = \dfrac{1}{3}, \  h(0) =0, \  h(2) =  \infty

b. Yes, <em>x ≠ 2</em>

Step-by-step explanation:

#3 The function is given as g(x) = -x² + 3

a. From the given function, by plugging in the value of 'x' in the bracket, we have;

g(-1) = -(-1)² + 3 = -1 + 3 = 2

g(-1) = 2

g(0) = -0² + 3 = 3

g(0) = 3

g(1) = -1² + 3 = -1 + 3 = 2

g(1) = 2

g(-1) = 2, g(0) = 3, and g(1) = 2

b. The given function g(x) = -x² + 3 for finding the value of <em>g</em> can take any value of <em>x</em> which is a real number

Therefore, therefore, there are no restrictions

#4 a. The given function is given as follows;

h(x) = \dfrac{x}{x - 2}

By substitution, we get;

h(-1) = \dfrac{-1}{(-1) - 2} = \dfrac{-1}{-3} = \dfrac{1}{3}

\therefore h(-1) = \dfrac{1}{3}

h(0) = \dfrac{0}{0 - 2} = \dfrac{0}{-2} =0

\therefore h(0) =0

h(2) = \dfrac{2}{2 - 2} = \dfrac{2}{0} = \infty

\therefore h(2) =  \infty

h(-1) = \dfrac{1}{3}, \  h(0) =0, \  h(2) =  \infty

b. From the values of the function, we have that h(x) is not defined at x = 2

Therefore, there is a restriction for <em>x</em> in the function, which is <em>x ≠ 2</em>

3 0
3 years ago
Solve and graph the inequality <br> -13&gt;5-2b
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Answer:

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Step-by-step explanation:

-13 > 5 - 2b

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You figure that your own >:(
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