Answer:
Below
Step-by-step explanation:
51)
Let n be the first even number.
So the four consecutive even numbers are:
● n
● n+2
● n+4
●n+6
The smallest minus twice the larger is 4
● n-2(n+6)= 4
●n-2n-12 =4
● -n -12 =4
● -12 = 4+n
● -12-4 = n
● -16 = n
so the first even number is -16 and the largest one is -10
● -16+6= -10
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Let m be the first integer
So the five consecutive integers are:
● m
● m+1
● m+2
● m+3
● m+4
The sum of this terms is 5.5 times the middle(m+2)
● m+m+1+m+2+m+3+m+4 = 5.5(m+2)
● 5m + 10 = 5.5 m +11
● -0.5 m = 1
●-m = 2
● m= -2
So the integers are;
● -2
● -1 (-2+1)
● 0
● 1
● 2
