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Goshia [24]
3 years ago
15

Two children are selling lemonade. They are charging $1 what situations could the other graphs represent

Mathematics
1 answer:
lina2011 [118]3 years ago
7 0

Answer:

Step-by-step explanation:

the answer is A

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PLEASE HELP! Last question! Which graphs show the solution to the given inequalities?
charle [14.2K]
1. A, It goes past the 4, but the circle is not shaded because the answer cannot be 4
2. C. It goes below the 11 and is shaded because it can be equal to 11
3. D. It is less than 13 and cannot equal thirteen, hence the non shaded circle
4. B. I goes past the -2 and has the circle shaded because it can be equal to the -2
7 0
3 years ago
Solve for x:<br> ( x - 2 ) ( x + 3 ) ( 2x - 7 ) = 0
Alika [10]

Answer:

x=2, x=-3, or x=3.5

Step-by-step explanation:

Make them all in 3 equations equal to 0. The number of brackets, the number of equations.  

6 0
3 years ago
A 40 N force is applied to an object with a mass of 0.1 kg on a frictionless surface. What is the acceleration of the object?
tino4ka555 [31]

Answer:

400

Step-by-step explanation:

40 divided by .1

4 0
4 years ago
I’m not sure what to do..
Arlecino [84]

Answer:

x=291/76

Step-by-step explanation:

Convert:

1/2x(6x+ 1/2)=-0.8x+16-1.2

Remove parenthesis and move terms:

3x+1/4=-0.8x+14.8

Collect the like terms and convert:

3x+0.8x=14.8-1/4

Subtract the fractions:

3.8x=74/5-1/4

Divide both sides by 3.8:

3.8x=291/20

x=291/76

7 0
3 years ago
Solve y=f(x) for x. Then find the input when the output is -3.
DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

f\left(x\right)\:=\:\left(x-5\right)^3-1

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

\:\:y=\:\left(x-5\right)^3-1

-3\:=\:\left(x-5\right)^3-1\:\:\:

switch sides

\left(x-5\right)^3-1=-3

Add 1 to both sides

\left(x-5\right)^3-1+1=-3+1

\left(x-5\right)^3=-2

\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

Thus, the input values are:

x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}

And the real input is:

x=-\sqrt[3]{2}+5

  • x=3.74
4 0
3 years ago
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