Are you by any chance referring to football? If you are, it is either a play in which by running or passing the offense moves down the field towards the opponent's endzone 15 yards, or it can be obtained by the defense committing an egregious penalty, such as a facemask, unsportsmanlike conduct, or unnecessary roughness.
Answer:
La altura del depósito para que pueda contener 1000 metros cúbicos de agua es 2 m.
Step-by-step explanation:
Para calcular el volumen de un prisma rectangular, es necesario multiplicar sus 3 dimensiones: longitud*ancho*altura. El volumen se expresa en unidades cúbicas.
En este caso, se conoce la longitud y el ancho, cuyos valores son 25 y 20 metros. A su vez, se sabe que el depósito de agua debe contener 1000 m³. Entonces, siendo:
Volumen= longitud*ancho*altura
Y reemplazando los valores se obtiene:
1000 m³= 25 m* 20 m* altura
Resolviendo:
1000 m³= 500 m²* altura
altura= 2 m
<u><em>La altura del depósito para que pueda contener 1000 metros cúbicos de agua es 2 m.</em></u>
<span>The diameter in centimeters (cm) of a human hair is about 0.0025 cm. In terms of scientific notation, it is written as 2.5 x 1</span><span>0^-3 cm</span>
So lets get to the problem
<span>165°= 135° +30° </span>
<span>To make it easier I'm going to write the same thing like this </span>
<span>165°= 90° + 45°+30° </span>
<span>Sin165° </span>
<span>= Sin ( 90° + 45°+30° ) </span>
<span>= Cos( 45°+30° )..... (∵ Sin(90 + θ)=cosθ </span>
<span>= Cos45°Cos30° - Sin45°Sin30° </span>
<span>Cos165° </span>
<span>= Cos ( 90° + 45°+30° ) </span>
<span>= -Sin( 45°+30° )..... (∵Cos(90 + θ)=-Sinθ </span>
<span>= Sin45°Cos30° + Cos45°Sin30° </span>
<span>Tan165° </span>
<span>= Tan ( 90° + 45°+30° ) </span>
<span>= -Cot( 45°+30° )..... (∵Cot(90 + θ)=-Tanθ </span>
<span>= -1/tan(45°+30°) </span>
<span>= -[1-tan45°.Tan30°]/[tan45°+Tan30°] </span>
<span>Substitute the above values with the following... These should be memorized </span>
<span>Sin 30° = 1/2 </span>
<span>Cos 30° =[Sqrt(3)]/2 </span>
<span>Tan 30° = 1/[Sqrt(3)] </span>
<span>Sin45°=Cos45°=1/[Sqrt(2)] </span>
<span>Tan 45° = 1</span>
