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3 years ago

Last year, Mary's vegetable garden was a rectangle that measured 6 ft by 8 ft.

Mathematics

2 answers:

Bess [88]3 years ago

8 0

Answer:

12 ft

Step-by-step explanation:

Bogdan [553]3 years ago

8 0

We can put the dimensions of Mary's garden into ratio format:

6ft by 8ft = 6ft : 8ft

Now if she increased it by a scale factor of 2=

6ft : 8ft = __ : 16ft

So we can see that 8 was multiplied by 2, so we do the same for 6:

6ft : 8ft = 12ft : 18ft.

So the measurements should be 12ft by 16ft

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16+5x=8x-5 What would the variable be?

11111nata11111 [884]

16+5x =8x-5

Reorder the terms
16+5x = -5+8x
Solving for variable for x

Move all terms containing x to the left, all other terms to the right.
Add -8x to each side of the equation.
16+ -3x = -5 + 8x + -8x

Combine like terms: 5x + -8x=-3x
16+-3x = -5 + 8x + -8x

Combine like terms: 8x + -8x = 0
16+-3x = -5 + 0
16+ -3x = -5

Add -16 to each side of the equation
16+-16 + -3x = -5 + 16

Combine like terms: 16+ -16 = 0
0 + -3x =-5 + -16
-3x = -5 + -16

combine like terms: -5 + -16 = -21
-3x = -21
Divide each side by -3
x=7

7 0

3 years ago

What is -3/5 multiplied by 4/7?<br> Pls show answer with step by step answers explained pls

zheka24 [161]

Answer:

-12/35

Step-by-step explanation:

-3×4/5×7

-12/35

7 0

3 years ago

Read 2 more answers

Y is between points p and b. pt= 15 and tb = 10. what is pb

Kruka [31]

PT = 15, and TB = 10

Take the 15 from PT, and add the 10 from TB. Which equals 25.

PB = 25

So, 25 is your answer.

Hope this helps! ☺

4 0

3 years ago

The length of a rectangle is one inch less than three times its width. If the perimeter of the rectangle is 118 inches, find the

IgorLugansk [536]

We can set up the width a X and, from the description the length would be 3X-1. The perimeter of a rectangle is determined by 2XL + 2Xw. Plugging into the equation 2(3X-1) + 2(X) = 118. Next distribute to get 6X-2 + 2X = 118. Combine like terms to get 8X = 120. Divide by 8 to get X = 15. The width is 15. The length is 3(15)-1 or 44. 88 +30 = 118

6 0

3 years ago

The scale on a map is 1: 75 000. (a) Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.

finlep [7]

Answer:

a. 1 200 000 km

b. 0.000 773 cm

c. 67 500 000 000 km²

d. 0.000 000 016 cm²

Step-by-step explanation:

a. Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.

Since the scale is 1 : 75000 that is 1 cm : 75000 km, we want to find the actual distance of 16 cm on the map. Let x be the actual distance in km.

So, 1 cm : 75000 km = 16 cm : x km

So, 1 cm/75000 km = 16 cm/x km

Thus x km = 16 cm × 75000 km/1 cm = 1 200 000 km

(b) Calculate length of a road on the map which is 0.58 km.

Let y be the length of road on the map. So, using our scale

1 cm : 75000 km = y cm : 0.58 km

So, 1 cm/75000 km = y cm/0.58 km

Thus y cm = 0.58 km × 1 cm/75000 km = 0.000 773 cm

(c) Calculate, in km², the ACTUAL area of a lake which is 12 cm2 on the map.

Since the scale is 1 : 75000 , the scale for the area would be the square of this. So, 1² : 75000² = 1 : 5 625 000 000 which is 1 cm² : 5 625 000 000 km²

Let z be the actual area of the lake.

So, 1 cm² : 5 625 000 000 km² = 12 cm² : z km²

So, 1 cm²/5 625 000 000 km² = 12 cm²/z km²

Thus z km² = 12 cm² × 5 625 000 000 km²/1 cm² = 67 500 000 000 km²

(d) Calculate the area of a play field on the map which has has an actual area of 90 km².

Let a represent the area of the play field on the map. Using our scale for the area,

1 cm² : 5 625 000 000 km² = a cm² : 90 km²

So, a cm² = 90 km² × 1/5 625 000 000 km² = 0.000 000 016 cm²

4 0

3 years ago