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3 years ago

Help with math 9th grade

Mathematics

1 answer:

g100num [7]3 years ago

8 0

Answer:

image 1

3. Common side

4. Hypotenuse side theorem

image 2

the ttiangles are congruent by side - angle - side test

image 3

angle p and t

angle q and s

side pq and ts

side qr and sr

side pr and tr

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Keith buys 45 tickets for rides at the amusement park. Each ride requires 6 tickets to ride. If Keith already has gone on x ride

FrozenT [24]

The answer is 45- (6 x <em>x)</em>

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3 years ago

A car travels 50 mph for 10 minutes. How many miles per minute is the car traveling? To the nearest tenth of a mile, how far doe

ozzi

We are required to convert the speed from miles per hour to miles per minute;
speed of the car=50 mph
the speed in miles per minute will be as follows;
1 hr=60 min
thus the speed will be given by:
speed=distance/time
=(50 miles)/(1 hours)
=(50 miles)/(60 min)
=5/6 m/min
thus the distance traveled in 10 min will be:
distance=speed*time
=5/6*10
=8 1/3 miles

7 0

3 years ago

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HELP ME FOR NUMBER 1 THROUGH 8 QUICKLY

Slav-nsk [51]

I did this last semester and I would remember it but unfortunately this was the only section I didn't study for the final bc we did one day on it. I'm sorry. Good luck.

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4 years ago

The resting heart rate for an adult horse should average about µ = 47 beats per minute with a (95% of data) range from 19 to 75

KatRina [158]

Answer:

a. 0.0582 = 5.82% probability that the heart rate is less than 25 beats per minute.

b. 0.1762 = 17.62% probability that the heart rate is greater than 60 beats per minute.

c. 0.7656 = 76.56% probability that the heart rate is between 25 and 60 beats per minute

Step-by-step explanation:

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean:

$\mu = 47$

(95% of data) range from 19 to 75 beats per minute.

This means that between 19 and 75, by the Empirical Rule, there are 4 standard deviations. So

$4\sigma = 75 - 19$

$4\sigma = 56$

$\sigma = \frac{56}{4} = 14$

a. What is the probability that the heart rate is less than 25 beats per minute?

This is the p-value of Z when X = 25. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{25 - 47}{14}$

$Z = -1.57$

$Z = -1.57$ has a p-value of 0.0582.

0.0582 = 5.82% probability that the heart rate is less than 25 beats per minute.

b. What is the probability that the heart rate is greater than 60 beats per minute?

This is 1 subtracted by the p-value of Z when X = 60. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 47}{14}$

$Z = 0.93$

$Z = 0.93$ has a p-value of 0.8238.

1 - 0.8238 = 0.1762

0.1762 = 17.62% probability that the heart rate is greater than 60 beats per minute.

c. What is the probability that the heart rate is between 25 and 60 beats per minute?

This is the p-value of Z when X = 60 subtracted by the p-value of Z when X = 25. From the previous two items, we have these two p-values. So

0.8238 - 0.0582 = 0.7656

0.7656 = 76.56% probability that the heart rate is between 25 and 60 beats per minute

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3 years ago

Solve for y:5y+2-2y=8y-4-2y

Agata [3.3K]

Answer: y=2
3y+2=6y-4
6=3y
y=2

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3 years ago

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Help with math *9th grade*

Help with math 9th grade