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2 years ago

Determine the value of x

Mathematics

2 answers:

Brut [27]2 years ago

6 0

It’s d brrooooooooooooo

scoundrel [369]2 years ago

6 0

Answer:

both angle 2x+60 and 4x+20 are equal

2x+60=4x+20

60=2x+20

40=2x

x=20

Step-by-step explanation:

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Phil has drawn some house plans in which the lounge room will be 9.5 m long when it is built. This length has been drawn as 19cm

Monica [59]

Answer:

1:50 scale

Step-by-step explanation:

9.5m * 100 = 950cm

950/19 = 50

7 0

3 years ago

Is the point (1, -3) a solution to the system? Show all work

Studentka2010 [4]

Answer:

The point P(1,-3) is not a solution to the system.

Step-by-step explanation:

Given $\left \{ {{y-x+2}} \right.$

Let a point be P(1,-3)

Here x = 1 ; y = -3

Substituting the values of x,y in the function

$\left \{ {{y-x+2}} \right.$

For y<x-1

-3 < 1-1

-3<0 (True)

now for,

y>-x+2

-3 > -1 + 2

-3 > 1 (False)

Hence the point is not a solution to the system.

6 0

3 years ago

[20 pts] evaluate the logarithm log(6)1/36, show work pls!

Delvig [45]

Answer:

$\large\boxed{\log_6\dfrac{1}{36}=-2}$

Step-by-step explanation:

$\text{We know:}\\\\\log_ab=c\iff a^c=b\\\\\log_6\dfrac{1}{36}\qquad\text{use}\ a^{-1}=\dfrac{1}{a}\\\\=\log_636^{-1}=\log_6(6^2)^{-1}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\log_66^{(2)(-1)}=\log_66^{-2}\qquad\text{use}\log_ab^n=n\log_ab\\\\=-2\log_66\qquad\text{use}\ \log_aa=1\\\\=-2(1)=-2$

$\log_6\dfrac{1}{36}=-2\ \text{because}\ 6^{-2}=\dfrac{1}{6^2}=\dfrac{1}{36}$

8 0

3 years ago

How do i solve 15=16x-11x

lyudmila [28]

You need to isolate x, which means you need to get it alone. 16x and 11x are like terms because they both have an x, do subtract them. 16-11=5. So 15 = 5x

Then to turn 5x into x, divide by five. This is because 5/5 is 1, and 1x is x. Divide both sides, so

X = 3

8 0

3 years ago

F(x)

mina [271]

a) Since both limits are distinct and do not exist, we conclude that x = - 1 is not part of the domain of the rational function.

b) The function $f(x) = \frac{x}{x^{2}+ x}$ is equivalent to the function $g(x) = \frac{1}{x + 1}$ .

<h3>How to determine whether a limit exists or not</h3>

According to theory of limits, a function f(x) exists for x = a if and only if $\lim_{x\to a^{-}} f(x) = \lim_{x \to a^{+}} f(x)$ . This criterion is commonly used to prove continuity of functions.

Rational functions are not continuous for all value of x, as there are x-values that make denominator equal to 0. Based on the figure given below, we have the following lateral limits:

$\lim_{x \to -1^{-}} \frac{x}{x^{2}+x} = - \infty$

$\lim_{x \to -1^{+}} \frac{x}{x^{2}+x} = + \infty$

Since both limits are distinct and do not exist, we conclude that x = - 1 is not part of the domain of the rational function.

In addition, we can simplify the function by algebra properties:

$\frac{x}{x^{2}+ x} = \frac{x}{x\cdot (x + 1)} = \frac{1}{x + 1}$

$g(x) = \frac{1}{x + 1}$

The function $f(x) = \frac{x}{x^{2}+ x}$ is equivalent to the function $g(x) = \frac{1}{x + 1}$ .

To learn more on lateral limits: brainly.com/question/21783151

#SPJ1

7 0

2 years ago