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Ira Lisetskai [31]
3 years ago
15

If x – 9 is a factor of x2 – 5x – 36, what is the other factor?

Mathematics
2 answers:
Luba_88 [7]3 years ago
5 0

Answer:

x + 4

Step-by-step explanation:

(x - 9)(x + 4)

FOIL

x^2 + 4x - 9x - 36 = x^2 - 5x - 36

Maru [420]3 years ago
5 0

Answer:

B

Step-by-step explanation:

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Answer:

58%

Step-by-step explanation:

This is because you need to set up the equation _ % of _ is _ and then plug in numbers. _% of 377 is 217 is the final equation. Then divide 217 by 377 which is 0.57559681697. Then you round to the nearest hundredth to get 58%

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Find the measure of angle A
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Answer:

105+50=155 so 180 subtract 155 is 25

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How do I find the slope from a table if the value added onto each (x,y) value is different? Please help!!! I need the slope!
Bess [88]
ANSWER:
________

Line q = 3
Line v = -1/2

FORMULA
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y2 - y1 / x2 - x1

EXPLANATION:
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First, we need to find the slope for line a only

We need to select two points from line q. The ones I selected are (-3,18) and (2,33)

y2 = 33
y1 = 18

x2 = 2
x1 = -3

33 - 18 = 15
2 - -3 = 5

15/5 = 3

Next, we need to find the slope for line v.

The two points I picked are (0,8) and (10,3)

y2 = 8
y1 = 3

x2 = 0
x1 = 10

8 - 3 = 5
0 - 10 = -10

5/-10 = -1/2

And that’s how you get your answer :)

PUN OF THE DAY
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Why did Adele cross the road? To say hello from the other side.

I hoped this helped! And have a •AMAZING• day :3
5 0
3 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

7 0
3 years ago
Write a description of -5a + 3 > 1 inequality
Andrej [43]

The sum of -5a and 3 is greater than 1

6 0
2 years ago
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