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mylen [45]
3 years ago
8

Change 26 out of 40 to a percentage

Mathematics
1 answer:
GenaCL600 [577]3 years ago
6 0

Answer:

65

Step-by-step explanation:

26 divided by 40 then multiply by a hundred

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Carry out three steps of the Bisection Method for f(x)=3x−x4 as follows: (a) Show that f(x) has a zero in [1,2]. (b) Determine w
ELEN [110]

Answer:

a) There's a zero between [1,2]

b) There's a zero between [1.5,2]

c) There's a zero between  [1.5,1.75].

Step-by-step explanation:

We have f(x)=3^x-x^4

A)We need to show that f(x) has a zero in the interval [1, 2]. We have to see if the function f is continuous with f(1) and f(2).

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(2)=3^2-(2)^4=9-16=(-7)

We can see that f(1) and f(2) have opposite signs. And f(1)>f(2) and the function is continuous, this means that exists a real number c between the interval [1,2] where f(c)=0.

B)We have to repeat the same steps of A)

For the subinterval [1,1.5]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1) and f(1.5) have the same signs, this means there's no zero in the subinterval [1,1.5].

For the subinterval [1.5,2]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.5) and f(2) have opposite signs, this means there's a zero between the subinterval [1.5,2].

C)We have to repeat the same steps of A)

For the subinterval [1,1.25]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5

f(1) and f(1.25) have the same signs, this means there's no zero in the subinterval [1,1.25].

For the subinterval [1.25,1.5]:

f(x)=3^x-x^4\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1.25) and f(1.5) have the same signs, this means there's no zero in the subinterval [1.25,1.5].

For the subinterval [1.5,1.75]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)

f(1.5) and f(1.75) have opposite signs, this means there's a zero between the subinterval [1.5,1.75].

For the subinterval [1.75,2]:

f(x)=3^x-x^4\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.75) and f(2) have the same signs, this means there isn't a zero between the subinterval [1.75,2].

The graph of the function shows that the answers are correct.

6 0
3 years ago
about 70,000 people live in a circular region with a 30-mile radius. find the population density in people per square mile.
bezimeni [28]

Solve for the area of the circular region first:

A = pi*r^2

A = pi*(30 mi)^2

A = 2827.43 mi^2

Density = 70000 people/2827.43 mi^2

Density = 24.76 = 25 people/mi^2 <--ANSWER Plz vote brainnliest


4 0
3 years ago
Which figure is shown?<br> prism<br> pyramid<br> cylinder<br> cone
hoa [83]
Hi, do you have to picture?
5 0
3 years ago
in the diagram, the length of S is 2/3 the length of T. If S has an area of 368 cm squared, find the perimeter of the figure.
vivado [14]
920 cm squared. Divide S by 2 then multiply to find the value of T. If S = 368 then T = 552, 368 + 552 = 920.
8 0
3 years ago
Given the function f(x) = 2|x + 6| -4, for what values of x is f(x) = 6?
photoshop1234 [79]

Answer:

f(x) = 2|x + 6|-4

6=2|x + 6|-4

10= 2|x + 6|

divide by 2

5=|x + 6|

x = 5-6

x = -1

so x should be -1

4 0
3 years ago
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