Diagonals of a parallelogram bisect each other
or they intersect each other in the halfway
x+4=3y-11-------------------------equation1
2x-1=y-1-------------------------------equation2
mulitply equation 1 to 2
2x+8=6y-22-----------------------equation3
equation2 - equation3
-9=-5y +21
5y=30
y=6
then x= 3
now PT=2x-1=5
TR=y-1=5
ST=3y-11=7
TQ=x+4=3+4=7
What? Is that two problems? I'll change my answer, give me my answer.
Answer:
x = 8.8 or x = 44/5
Step-by-step explanation:
1) Multiply both sides of the equation by 4, and cancel out the 4 on the bottom of 3/4, this turns the equation into: 8x - 4 = 3x + 40
2) Move the x to the lefthand side and change the side, do the same for the constant (4), this turns the equation into: 8x - 3x = 40 + 4
3) Combine like terms, subtract 8x from 3x and add 40 to 4: 5x = 44
4) Divide both sides by 5, and your answer is 44/5 (or 8.8 when converted to a decimal)
12 in all:
{2, 4, 36, 6, 8, 10, 12, 16, 18, 20, 24, 30}
Answer:
Step-by-step explanation:
Answer:
The answer is 1/42 as you take reciprocal of 6=(1/6) and reciprocal of 7=(1/7) and multiply.