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inn [45]
3 years ago
14

Why might a scientist studying water pollution work with percents less than one?

Mathematics
1 answer:
34kurt3 years ago
7 0
Because, often times, water pollutants occur in small amounts. Therefore, it is likely to use small percentages (less than 1%) in comparison to the water and various other pollutants in the same sample.
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Find the difference of(ab+8a+1)-(-6ab+4)
vagabundo [1.1K]
Hey there!

When finding the difference of expressions like these, there's a few things you should keep in mind. 

1. When finding the difference of two polynomials, multiply the polynomial that implied to be "negative" by –1 to expand the problem and make it easier to solve. 

2. You combine terms based on their unknown terms, like x, y, x², ab, etc. You cannot combine the terms x and x², but you can combine the terms 6b and 8b by adding them. 

3. You can rearrange your terms however you see fit. If a polynomial is implied as "positive", you can multiply that entire polynomial by +1 to get rid of the parentheses. 

With all that in mind, you can go ahead and solve for your difference, like so:

(ab+8a+1)-(-6ab+4)

(ab+8a+1) (-1(-6ab+4))

(ab+8a+1) + (6ab-4)

ab+6ab+8a+1-4

7ab+8a-3

7ab+8a-3 will be your difference. 

Hope this helped you out! :-)
8 0
3 years ago
A. - 3x - 2y = 4
weeeeeb [17]

Answer:it’s .a

Step-by-step explanation:

7 0
3 years ago
Shannon saves 1235 in november. In november, she saved $250 less than she did in december. How much money did she save in the tw
madam [21]
In December she would have saved $1585 because 1235 + 250 = 1485. You can find how much money she raised in those 2 months by adding the totals of both months together, so 1485 + 1235 = 2720. She saved $2720 in the 2 months.
4 0
3 years ago
Please please help me!!
podryga [215]
Answer: square root of three or 1.73205

Hope this helps :)
5 0
3 years ago
Read 2 more answers
What are the real roots of 2x^3+9x^2+4x-15=0
klemol [59]
Well, luckily it is apparent that (x-1) is a root because when x=1 the equation is equal to zero.  So we can divide the equation by that factor to find the other roots. 

(2x^3+9x^2+4x-15)/(x-1)
2x^2  r  11x^2+4x-15
11x    r  15x-15
15     r   0

(x-1)(2x^2+11x+15)=0

(x-1)(2x^2+6x+5x+15)=0

(x-1)(2x(x+3)+5(x+3))=0

(x-1)(2x+5)(x+3)=0

So the roots are x= -3, -2.5, 1
8 0
3 years ago
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