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alekssr [168]
3 years ago
12

A pecan pie is being served for dessert. One piece of pie has an arc length of 7.85 in. It has been cut into 8 equal pieces. Wha

t is the radius of the pecan pie? (Round to the nearest whole number)
Mathematics
1 answer:
pishuonlain [190]3 years ago
8 0

Answer: 10 inches.

Step-by-step explanation:

Since the pecan pie is a circle, you can use this formula:

arc\ length=r\theta

Where "r" is the radius and \theta is the central angle of the arc in radians.

If the pecan pie has been cut into 8 equal pieces then the central angle is:

\theta=\frac{2\pi}{8}\\\\\theta={\frac{\pi}{4}

Now you know the arc length and the central angle, then, you can solve for "r" from  arc\ length=r\theta:

 \frac{arc\ length}{\theta} =r

Substituting values, you get that the radius of the pecan pie rounded to the nearest whole number is:

r=\frac{7.85in}{\frac{\pi}{4}}\\\\r=10in

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AnnZ [28]
Yes, it is an irrational number because it can’t be written as a fraction

Negative square root of 35 is about -5.92, it can’t be written as a fraction

Rational number: can be written as a fraction
Irrational number: can’t be written as a fraction

I hope this helps!
5 0
3 years ago
during a 500-meter race, a runner ran the first 400 meters in 1 minute and 25 seconds.she finished the race i 2 minutes and 15 s
mart [117]

She ran the last 100 meters in 2:15 -1:25 = 0:50, so her average speed was

... (100 m)/(50 s) = 2.0 m/s

6 0
4 years ago
What is the sum of <br> 4 1/2 + 1 3/5 in simplest form ?
olga2289 [7]

Answer:

Step-by-step explanation:

Convert the mixed numbers to improper fractions, then find the LCD and combine.

Exact Form:

61 /  10

 

Decimal Form:

6.1  

Mixed Number Form:

6 1/10  

6 0
3 years ago
Round 17.641 to the nearest whole number
vfiekz [6]
The nearest whole number would be 18 because the 6 is greater than 5. Anything greater than five, would most likely be rounded to the nearest whole number. Hope this helped!


8 0
3 years ago
4/x-1+6/x+1=-12/x^2-1
Mademuasel [1]
\frac{4}{x - 1} + \frac{6}{x + 1} = \frac{-12}{x^{2} - 1}

\frac{4(x + 1)}{(x - 1)(x + 1)} + \frac{6(x - 1)}{(x - 1)(x + 1)} = \frac{-12}{x^{2} - 1}

\frac{4x + 4}{x^{2} - 1} + \frac{6x - 6}{x^{2} - 1} = \frac{-12}{x^{2} - 1}

\frac{10x - 2}{x^{2} - 1} = \frac{-12}{x^{2} - 1}

(10x - 2)(x^{2} - 1) = -12(x^{2} - 1)
10x^{3} - 10x^{2} - 2x^{2} + 2 = -12(x^{2}) + 12(1)
10x^{3} - 12x^{2} + 2 = -12x^{2} + 12
10x^{3} - 12x^{2} + 12x^{2} + 2 = -12x^{2} + 12x^{2} + 12
10x^{3} + 2 - 2 = 12 - 2
\frac{10x^{3}}{10} = \frac{10}{10}

x^{3} = 1
x = 1
4 0
3 years ago
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