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My name is Ann [436]
3 years ago
9

What are the zeros of this function?

Mathematics
1 answer:
raketka [301]3 years ago
3 0

Answer:

the zeros of a function are called the numbers in which you substitute 'x' to make a value of zero

I hope this makes sense, and hope it helps you

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16) (5x +2)(7x - 2)<br> Ayoo can someone answer that man
algol [13]
(16) (12) (12) is the answer I think
5 0
3 years ago
Answer from least to greatest 9 -11 -8 12 3
Thepotemich [5.8K]
\begin{gathered} -11 \\ -8 \\ 3 \\ 9 \\ 12 \end{gathered}

remember a number is least when

3 0
1 year ago
Which equation represents a line parallel to the line shown on the graph?
Delicious77 [7]

The  equation y=2x+1 has the same slope , so will be parallel to the given line.

<h3>What is a linear function ?</h3>

A function that can be represented in the form of y =mx +c , is called a Linear Function.

here m is the slope and c is the y intercept.

The slope of the given line can be found as follows

The y intercept is 4

at x = -2 , y =0

0 = -2m + 4

m = 2

The line parallel to this line will have the same slope

In the given option , Option C , y=2x+1 has the same slope , so will be parallel to the given line.

To know more about Linear Function

brainly.com/question/21107621

#SPJ1

3 0
2 years ago
A silo is in the shape of a cone. The silo is 7 meters tall, and its base has a radius of 1.5 meters. Rice costs 204$ per cubic
olganol [36]

Answer:

  $3364.65

Step-by-step explanation:

The volume of the cone is given by the formula ...

  V = (1/3)πr²h

Filling in the given numbers, we find the volume to be ...

  V = (1/3)π(1.5 m)²(7 m) = 5.25π m³ ≈ 16.49336 m³

The cost of the rice will be the product of this volume and the price per cubic meter:

  cost = (16.49336 m³)($204/m³) = $3364.65

The cost of the rice necessary to fill the volume is $3364.65.

_____

<em>Comment on pi</em>

If you use the value 3.14 for pi, the cost comes to $3362.94. A 3-digit value of pi only gives an answer good in its first 3 digits.

3 0
3 years ago
Factor by grouping: 2v^3 + 3v^2 + 4v + 6
dimulka [17.4K]
<span>2v^3 + 3v^2 + 4v + 6
= (</span><span>2v^3 + 3v^2)  + (4v + 6)
= v^2 (2v + 3) + 2 (2v + 3)
= (v^2 + 2)(2v + 3)

hope it helps</span>
3 0
3 years ago
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