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vesna_86 [32]
3 years ago
14

(I will mark brainliest if you can get it correct) Hot chocolate is made with milk warmed to 172∘F with an error tolerance of 6%

. What is the acceptable temperature range for milk when making hot chocolate?
A. 170.968∘F to 173.032∘F


B. 161.68∘F to 182.32∘F


C. 171.4∘F to 172.6∘F


D. 166∘F to 178∘F
Mathematics
2 answers:
laiz [17]3 years ago
7 0

Answer:

161.68°F to 182.32°F

Step-by-step explanation:

6%=6/100= 0.06

0.06×172=10.32°F

thus temperature range is

(172 + or - 10.32)°F

tangare [24]3 years ago
5 0
D cuz I feel like it is
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(a) The 5-hour decay factor is 0.5042.

(b) The 1-hour decay factor is 0.8720.

(c) The amount of caffeine in Chase's body 2.39 hours after consuming the drink is 149.112 mg.

Step-by-step explanation:

The amount of caffeine in Chase's body decreases exponentially.

The 10-hour decay factor for the number of mg of caffeine is 0.2542.

The 1-hour decay factor is:

1-hour\ decay\ factor=(0.2542)^{1/10}=0.8720

(a)

Compute the 5-hour decay factor as follows:

5-hour\ decay\ factor=(0.8720)^{5}\\=0.504176\\\approx0.5042

Thus, the 5-hour decay factor is 0.5042.

(b)

The 1-hour decay factor is:

1-hour\ decay\ factor=(0.2542)^{1/10}=0.8720

Thus, the 1-hour decay factor is 0.8720.

(c)

The equation to compute the amount of caffeine in Chase's body is:

A = Initial amount × (0.8720)<em>ⁿ</em>

It is provided that initially Chase had 171 mg of caffeine, 1.39 hours after consuming the drink.

Compute the amount of caffeine in Chase's body 2.39 hours after consuming the drink as follows:

A = Initial\ amount \times (0.8720)^{2.39} \\=[Initial\ amount \times (0.8720)^{1.39}] \times(0.8720)\\=171\times 0.8720\\=149.112

Thus, the amount of caffeine in Chase's body 2.39 hours after consuming the drink is 149.112 mg.

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