We have that
f(x) = –4x²<span> + 24x + 13
</span>
we know that
The vertex form for a parabola that opens up or down is:
f(x) = a(x - h)^2 + k
in the given equation, <span>a=-4</span><span>, therefore we add zero to the original equation in the form of </span><span>4h</span>²<span>−4h</span>²
f(x) = –4x² + 24x + 4h²−4h² +13
<span>Factor 4 out of the first 3 terms and group them
</span>f(x) = –4*(x² -6x +h²) +4h² +13
<span>We can find the value of h by setting the middle term equal to -2hx
</span>−2hx=−6x
<span>h=3</span><span> and </span><span>4h</span>²<span>=<span>36
</span></span>f(x) = –4*(x² -6x +9) +36 +13
we know that the term (x² -6x +9) is equals to------> (x-3)²
so
f(x) = –4*(x-3)² +49
the answer isf(x) = –4*(x-3)² +49
Given in the problem is the diameter of the Ferris Wheel.
Thus, we can compute for the Ferris Wheel Circumference. This is the circular distance a single capsule attached to the wheel needs to do a full circle to.
Using 2 Step, we find the rate of how fast the capsule needs to be moving to complete 1 full cycle in 30 minutes.
1. Formula for computing the circumference
C = 2 x π x R
where R = Diameter divided by 2
C = 2π(120/2 )
C = 120π
2. Compute the rate or speed of the capsule / coach.
Rate or Speed = Distance to cover / Time it takes to cover
R/S = 120π/30 = 4π m/min or 12.57737 meters / min
c. 35 + 50x ≤ 1,325
Step-by-step explanation:
Abbey's total cost must be less then or equal to her total savings, i.e.
cost ≤ savings
it is given that cost = fixed registration fee and a monthly fee of $50 per month. Hence,
fixed registration + (monthly fee)*(number of months) ≤ savings
let the number of months be x,
hence
35 + 50x ≤ 1325(c)
Answer:
AC ≈ 5.03
Step-by-step explanation:
We can solve the problem above using the trigonometric ratio, they are;
SOH CAH TOA
sin Ф = opposite / hypotenuse
cosФ= adjacent/ hypotenuse
tan Ф = opposite / adjacent
From the diagram above, in reference to angle B;
opposite =AC and adjacent =BC
Since we have opposite and adjacent, the best formula to use is
tanФ = opposite / adjacent
tan B = AC / BC
tan 40 = AC/ 6
Multiply both-side of the equation by 6
6× tan 40 = AC/ 6 × 6
At the right-hand side of the equation, 6 will cancel-out 6 leaving us with just AC
6×tan 40 = AC
5.034598 = AC
AC ≈ 5.03 to the nearest hundredths
