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ira [324]
3 years ago
6

Does any one know how to do this

Mathematics
2 answers:
Ksju [112]3 years ago
8 0
Hope this helps you
angle ?= 41.8°

yuradex [85]3 years ago
6 0
Use pathagerium theorm (a2+b2=c2)
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1 year ago
Inverse laplace transform of H(s) = 1/(s+4)^2
ziro4ka [17]

Answer:

Inverse Laplace of \frac{1}{(S+4)^2} will be te^{-4t}

Step-by-step explanation:

We have to find the inverse Laplace transform of H(S)=\frac{1}{(S+4)^2}

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As in H(s) there is square of s+4

So i inverse Laplace there will be multiplication of t

So the inverse Laplace of \frac{1}{(s+4)^2}  will be te^{-4t}

L^{-1}\frac{1}{(S+4)^2}=te^{-4t}

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3 years ago
The rule R x-axis ∘ T⟨–5, 3⟩ is applied to the point (–3, –2). Where is the image in the coordinate system?
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Given:

Rule of transformation is rule R x-axis ∘ T⟨–5, 3⟩.

The point is (-3,-2).

To find:

The image of given point after the transformation.

Solution:

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P'(-8,1)\to P''(-8,-1)

Therefore, the image of given point after transformation is (-8,-1).

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In the diagram, ATPR ~ AXPZ. Find the length of the altitude PY
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