The answer for your problem is x = 26
see the attached figure to better understand the problem
we have that

Step 1
<u>Find the value of AC</u>
we know that
in the right triangle ABC

substitute the values in the formula

Step 2
<u>Find the value of BC</u>
we know that
in the right triangle ABC
Applying the Pythagorean Theorem

substitute the values

Step 3
<u>Find the value of BD</u>
we know that
in the right triangle BCD
Applying the Pythagorean Theorem

substitute the values


therefore
<u>the answer is</u>
the length of BD is 11.93 units
Here, Equation: 4x + 2y = 4
Divide the equation by 2,
2x + y = 2
y = -2x + 2
Now, compare the equation with y = mx + c
Here, slope (m) = -2
In short, Your Answer would be -2
Hope this helps!
Since the problem is given all the total walking distance, the first thing we are going to do is find the total distance in the map:


Now that we have the distance in the map, we can establish a ratio between the walking distance and the distance in the map:

We can conclude that each inch the map represents 0.5 miles of walking distance.