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Tpy6a [65]
2 years ago
14

This connects to the last one I did

Mathematics
2 answers:
vichka [17]2 years ago
4 0
-4x+3 and -2y idk if that's completely right tho
lana [24]2 years ago
4 0
Wrong. The first one is -6x + 3
The second one is 0
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WILL MARK BRANLIEST<br><br> the first one plz
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Answer:

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Step-by-step explanation:

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2 years ago
8 There are a combined 33 students who play a spring sport of track or
Rzqust [24]

The number of students that are on the track team are 18.

The number of students that are on the baseball team are 15.

<h3>What are the linear equations that represent the question?</h3>

a + b = 33 equation 1

a - b = 3 equation 2

Where:

  • a = number of students that are on the track team
  • b = number of students that are on the baseball team

<h3>How many students that are on the baseball team?</h3>

Subtract equation 2 from equation 1

2b = 30

Divide both sides by 2

b = 30/2 = 15

<h3>How many students that are on the track team?</h3>

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2 years ago
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2 years ago
WILL GIVE BRAINLIEST Chang deposited $5000 into an account with a 4.8% annual interest rate, compounded monthly. Assuming that n
Mariulka [41]

Answer:

9.42 years (= 113 months)

Step-by-step explanation:

Use the compound rate interest formula:

A=P(1+\frac{r}{n})^{nt}

where:

  • A = amount
  • P = principal
  • r = interest rate (in decimal format)
  • n = number of times interest is compounded per unit t
  • t = time

Given:

  • A = $7850
  • P = $5000
  • r = 4.8% = 0.048
  • n = 12
  • t = years

\implies 7850=5000(1+\frac{0.048}{12})^{12t}

\implies 7850=5000(1.004)^{12t}

\implies \dfrac{7850}{5000}=(1.004)^{12t}

\implies 1.57=(1.004)^{12t}

Take natural logs:

\implies \ln1.57=\ln(1.004)^{12t}

\implies \ln1.57=12t\ln(1.004)

\implies t=\dfrac{\ln 1.57}{12 \ln1.004}

\implies t=9.42\textsf{ years (nearest hundredth)}

\implies t=113 \textsf{ months}

5 0
1 year ago
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