Question

How do you solve this equation 4-2(v-6)=-8

Answer 1

Answer:

first, subtract 4 from each side of the equation to isolate the term with parenthesis while keeping the equation balanced:

−4+4−2(v−6)=−4−8

0−2(v−6)=−12

−2(v−6)=−12

Next, divide each side of the equation by −2 to eliminate the need for parenthesis while keeping the equation balanced:

−2(v−6)−2=−12−2

−2

(v−6)−2

=6

v−6=6

Then, add 6 to each side of the equation to solve for v term while keeping the equation balanced:

v−6+6=6+6

v−0=12

v=12

Answer 2

I couldn’t really crop the whole pic for the answer but like , at the begginimg you have to Distribute -2 through the parenthesis , so it’s gonna be “4-2v+12=8” and then you have to add so it’s gonna be “16-2v=8” now you Move constant to the right side and change its sign soo, “ -2v=8-16” then you calculate them difference which is “-2v=-8” after you Divide both sides of the equation by -2 and the whole think would equal “V=4”